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If the eccentricity of an ellipse be 5/8 and the distance between its foci be 10, then its latus rectum is
  • a)
    39/4
  • b)
    12
  • c)
    15
  • d)
    37/2
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
If the eccentricity of an ellipse be 5/8 and the distance between its ...
To find the latus rectum of the ellipse, we need to first determine the length of the major axis.

Given:
Eccentricity (e) = 5/8
Distance between foci (2ae) = 10

Let's denote the major axis as 2a and the minor axis as 2b.

Using the formula for the distance between foci:
2ae = 10
(2)(5/8)(a) = 10
(5/4)(a) = 10
a = 10 * (4/5)
a = 8

Now, let's find the value of b using the eccentricity:
e = c/a
5/8 = c/8
c = 5

So, the coordinates of the foci are (-c, 0) and (c, 0), which are (-5, 0) and (5, 0) respectively.

The equation of the ellipse in standard form is given by:
x^2/a^2 + y^2/b^2 = 1

Substituting the values of a and b, we get:
x^2/8^2 + y^2/b^2 = 1
x^2/64 + y^2/b^2 = 1

Now, let's find the length of the latus rectum:
The length of the latus rectum is given by the formula 2b^2/a.

Substituting the values of a and b, we get:
2b^2/a = 2(8^2)/8 = 16

Therefore, the length of the latus rectum is 16.
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If the eccentricity of an ellipse be 5/8 and the distance between its foci be 10, then its latus rectum isa)39/4b)12c)15d)37/2Correct answer is option 'A'. Can you explain this answer?
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