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If the distance between the foci of an ellipse is 6 and the distance between its directrices is 12, then the length of its latus rectum is
  • a)
    2√3
  • b)
    √3
  • c)
    3/√2
  • d)
    3√2
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
If the distance between the foci of an ellipse is 6 and the distance b...
Given,
2ae = 6 .... (1)
∴ ae = 3
Also,
2a/e = 126 .... (2)
∴ a/e = 63
From (1) and (2),

Since b2 = a2(1 - e2)
Substitute the values of 'e' and 'a' in the above equation.
⇒ b2 = 9
∴ b = ±3
Length of latus rectum 
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Community Answer
If the distance between the foci of an ellipse is 6 and the distance b...
The length of the latus rectum of an ellipse is given by the equation:

latus rectum = 2b^2/a

where a is the distance between the center of the ellipse and one of its vertices, and b is the distance between the center of the ellipse and one of its co-vertices.

In this case, the distance between the foci of the ellipse is 6, so a = 6/2 = 3.

The distance between the directrices of the ellipse is 12, so b = 12/2 = 6.

Substituting these values into the equation for the length of the latus rectum, we get:

latus rectum = 2(6^2)/3 = 2(36)/3 = 2(12) = 24

Therefore, the length of the latus rectum of the ellipse is 24.
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If the distance between the foci of an ellipse is 6 and the distance between its directrices is 12, then the length of its latus rectum isa)2√3b)√3c)3/√2d)3√2Correct answer is option 'D'. Can you explain this answer?
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