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If tan (A/2) = x, then the value of x is (SSC CHSL 2017)
- a)sin A/(1 – cosA)
- b)sin A/(1 + cosA)
- c)cos A/(1+sin A)
- d)cos A/(1 – sin A)
Correct answer is option 'B'. Can you explain this answer?
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If tan (A/2) = x, then the value of x is (SSC CHSL 2017)a)sin A/(1 &n...
To find the value of x, we can use the half-angle identity for tangent:
tan(A/2) = sin(A) / (1 + cos(A))
From the given equation, we have:
tan(A/2) = x
Using the half-angle identity, we can rewrite the equation as:
x = sin(A) / (1 + cos(A))
So, the value of x is sin(A) / (1 + cos(A)).
tan(A/2) = sin(A) / (1 + cos(A))
From the given equation, we have:
tan(A/2) = x
Using the half-angle identity, we can rewrite the equation as:
x = sin(A) / (1 + cos(A))
So, the value of x is sin(A) / (1 + cos(A)).
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