To find the value of x, we need to solve for x in the equation 47x * 3y2 = 16279.

First, let's break down the number 16279:
16279 = 1 * 10^4 + 6 * 10^3 + 2 * 10^2 + 7 * 10^1 + 9 * 10^0
= 10000 + 6000 + 200 + 70 + 9

Since 47x is a three-digit number, it must be greater than or equal to 100 and less than 1000. Therefore, the thousands digit of 47x must be 1.

Let's subtract the value of 10000 from 16279 to see what's left:
16279 - 10000 = 6279

Now we need to find two integers whose product equals 6279. These integers are the possible values of 3y2.

Let's try dividing 6279 by different numbers to find a pair of integers that multiply to give 6279:

6279 ÷ 1 = 6279
6279 ÷ 3 = 2093
6279 ÷ 9 = 697
6279 ÷ 11 = 570
6279 ÷ 13 = 483
6279 ÷ 21 = 299
6279 ÷ 33 = 190
6279 ÷ 39 = 161
6279 ÷ 57 = 110
6279 ÷ 77 = 81
6279 ÷ 99 = 63

From the above calculations, we can see that the pair of integers whose product equals 6279 is 77 and 81.

Therefore, we can conclude that 3y2 = 77 and 47x = 81.

To find the value of x, we divide 81 by 47:
81 ÷ 47 = 1.7234

Since x must be a digit, the value of x is rounded down to the nearest whole number, which is 1.

Therefore, the value of x is 1.