Find the product of two consecutive numbers where four times the first...
To find the product of two consecutive numbers, we need to let the first number be represented by x, and the second number be represented by x+1.
Given that four times the first number is 10 more than thrice the second number, we can form the equation:
4x = 3(x+1) + 10
Now, let's solve the equation step by step:
4x = 3x + 3 + 10 (Distribute 3 to x+1)
4x - 3x = 13 (Combine like terms)
x = 13 (Divide both sides by x)
So, the first number is 13 and the second number is 13+1 = 14.
To find the product of these two consecutive numbers:
Product = 13 * 14 = 182
Therefore, the correct answer is option B) 182.
Find the product of two consecutive numbers where four times the first...
Given:
Four times the first number is 10 more than thrice the second number.
Calculation:
Suppose the numbers are ‘a’ and ‘a + 1’.
According to the question :
4a = 3 × (a + 1) + 10
⇒ a = 13
Hence, the numbers are 13 and 14.
∴ Product = 13 × 14 = 182