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A car is moving towards check post with velocity 96kmph . when car is at 100m from check post, driver applies brake which is caused by deceleration of 3mpsq.s . find the distance of the car from check post, for 1minutes after applying brakes?
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A car is moving towards check post with velocity 96kmph . when car is ...
**Given:**
- Initial velocity of the car = 96 km/h = 96 × (5/18) m/s = 26.67 m/s
- Distance of the car from check post = 100 m
- Deceleration of the car = -3 m/s² (negative sign indicates deceleration)
**To find:**
- Distance of the car from check post after 1 minute of applying brakes
**Formula Used:**
- The equation of motion used in this scenario is:
- v = u + at
- s = ut + (1/2)at²
**Calculation:**
- Given initial velocity (u) = 26.67 m/s
- Deceleration (a) = -3 m/s²
- Time (t) = 1 minute = 1 × 60 = 60 seconds
**Step 1: Calculate the final velocity of the car.**
- Using the equation v = u + at, we can find the final velocity (v) of the car after 1 minute:
- v = u + at
- v = 26.67 - 3 × 60
- v = 26.67 - 180
- v = -153.33 m/s (negative sign indicates opposite direction of initial velocity)
**Step 2: Calculate the distance traveled by the car in 1 minute.**
- Using the equation s = ut + (1/2)at², we can find the distance (s) traveled by the car in 1 minute:
- s = ut + (1/2)at²
- s = 26.67 × 60 + (1/2)(-3)(60)²
- s = 1600.2 - 5400
- s = -3799.8 m (negative sign indicates opposite direction of initial displacement)
**Step 3: Calculate the distance of the car from the check post after 1 minute.**
- The distance of the car from the check post after 1 minute can be calculated by subtracting the distance traveled by the car from the initial distance:
- Distance = Initial distance - Distance traveled
- Distance = 100 - (-3799.8)
- Distance = 100 + 3799.8
- Distance = 3899.8 m
**Therefore, the distance of the car from the check post after 1 minute of applying brakes is 3899.8 meters.**
- Initial velocity of the car = 96 km/h = 96 × (5/18) m/s = 26.67 m/s
- Distance of the car from check post = 100 m
- Deceleration of the car = -3 m/s² (negative sign indicates deceleration)
**To find:**
- Distance of the car from check post after 1 minute of applying brakes
**Formula Used:**
- The equation of motion used in this scenario is:
- v = u + at
- s = ut + (1/2)at²
**Calculation:**
- Given initial velocity (u) = 26.67 m/s
- Deceleration (a) = -3 m/s²
- Time (t) = 1 minute = 1 × 60 = 60 seconds
**Step 1: Calculate the final velocity of the car.**
- Using the equation v = u + at, we can find the final velocity (v) of the car after 1 minute:
- v = u + at
- v = 26.67 - 3 × 60
- v = 26.67 - 180
- v = -153.33 m/s (negative sign indicates opposite direction of initial velocity)
**Step 2: Calculate the distance traveled by the car in 1 minute.**
- Using the equation s = ut + (1/2)at², we can find the distance (s) traveled by the car in 1 minute:
- s = ut + (1/2)at²
- s = 26.67 × 60 + (1/2)(-3)(60)²
- s = 1600.2 - 5400
- s = -3799.8 m (negative sign indicates opposite direction of initial displacement)
**Step 3: Calculate the distance of the car from the check post after 1 minute.**
- The distance of the car from the check post after 1 minute can be calculated by subtracting the distance traveled by the car from the initial distance:
- Distance = Initial distance - Distance traveled
- Distance = 100 - (-3799.8)
- Distance = 100 + 3799.8
- Distance = 3899.8 m
**Therefore, the distance of the car from the check post after 1 minute of applying brakes is 3899.8 meters.**
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A car is moving towards check post with velocity 96kmph . when car is at 100m from check post, driver applies brake which is caused by deceleration of 3mpsq.s . find the distance of the car from check post, for 1minutes after applying brakes?
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A car is moving towards check post with velocity 96kmph . when car is at 100m from check post, driver applies brake which is caused by deceleration of 3mpsq.s . find the distance of the car from check post, for 1minutes after applying brakes? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A car is moving towards check post with velocity 96kmph . when car is at 100m from check post, driver applies brake which is caused by deceleration of 3mpsq.s . find the distance of the car from check post, for 1minutes after applying brakes? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car is moving towards check post with velocity 96kmph . when car is at 100m from check post, driver applies brake which is caused by deceleration of 3mpsq.s . find the distance of the car from check post, for 1minutes after applying brakes?.
A car is moving towards check post with velocity 96kmph . when car is at 100m from check post, driver applies brake which is caused by deceleration of 3mpsq.s . find the distance of the car from check post, for 1minutes after applying brakes? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A car is moving towards check post with velocity 96kmph . when car is at 100m from check post, driver applies brake which is caused by deceleration of 3mpsq.s . find the distance of the car from check post, for 1minutes after applying brakes? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car is moving towards check post with velocity 96kmph . when car is at 100m from check post, driver applies brake which is caused by deceleration of 3mpsq.s . find the distance of the car from check post, for 1minutes after applying brakes?.
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