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From 125 metre high towers, the angle of depression of a car is 45°. Then how far the car is from the tower? (SSC CGL 1st Sit. 2013)
- a)125 metre
- b)60 metre
- c)75 metre
- d)95 metre
Correct answer is option 'A'. Can you explain this answer?
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From 125 metre high towers, the angle of depression of a car is 45°...
The angle of depression is the angle between the horizontal line of sight and the line of sight from an observer to a point below the observer. In this case, the angle of depression of the car is 45 degrees.
To find the horizontal distance between the car and the base of the tower, we can use trigonometry. Given that the height of the tower is 125 meters, we can consider this as the opposite side (O) of a right triangle.
Using the tangent function, we have:
tan(angle) = opposite/adjacent
tan(45 degrees) = 125 meters/adjacent
Simplifying, we have:
1 = 125 meters/adjacent
To find the adjacent side (A), we can multiply both sides by A:
A = 125 meters
Therefore, the horizontal distance between the car and the base of the tower is 125 meters.
To find the horizontal distance between the car and the base of the tower, we can use trigonometry. Given that the height of the tower is 125 meters, we can consider this as the opposite side (O) of a right triangle.
Using the tangent function, we have:
tan(angle) = opposite/adjacent
tan(45 degrees) = 125 meters/adjacent
Simplifying, we have:
1 = 125 meters/adjacent
To find the adjacent side (A), we can multiply both sides by A:
A = 125 meters
Therefore, the horizontal distance between the car and the base of the tower is 125 meters.
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From 125 metre high towers, the angle of depression of a car is 45°...
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From 125 metre high towers, the angle of depression of a car is 45°. Then how far the car is from the tower? (SSC CGL 1st Sit. 2013)a)125 metreb)60 metrec)75 metred)95 metreCorrect answer is option 'A'. Can you explain this answer?
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