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What is the output of the following code?
num = 10
for i in range(2, num):
    if num % i == 0:
        print("Not a prime number")
        break
else:
    print("Prime number")
  • a)
    Not a prime number
  • b)
    Prime number
  • c)
    Not a prime number Prime number
  • d)
    No output
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
What is the output of the following code?num = 10for i in range(2, num...
The code is incomplete as it does not have a closing parenthesis. The correct code should be:

num = 10
for i in range(2, num):
if num % i == 0:
print(i)

The output of this code would be:
2
5

This is because the code is checking for factors of 10. It starts at 2 and checks if 10 is divisible by 2, which it is. Therefore, it prints 2. It then continues to check if 10 is divisible by 3, 4, 5, 6, 7, 8, or 9, but it is not divisible by any of these numbers. So, it does not print any additional numbers.
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Community Answer
What is the output of the following code?num = 10for i in range(2, num...
The loop iterates over the range range(2, num), which generates the numbers from 2 to num-1. It checks if num is divisible by any number and prints "Not a prime number" if a factor is found. If the loop completes without finding any factors, it prints "Prime number."
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What is the output of the following code?num = 10for i in range(2, num): if num % i == 0: print("Not a prime number") breakelse: print("Prime number")a)Not a prime numberb)Prime numberc)Not a prime number Prime numberd)No outputCorrect answer is option 'B'. Can you explain this answer?
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