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What is the output of the following code snippet?
for i in range(5):
if i == 2:
break
print(i)
for i in range(5):
if i == 2:
break
print(i)
- a)0 1 2
- b)0 1
- c)0 1 3 4
- d)0 1 3
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
What is the output of the following code snippet?for i in range(5): i...
Understanding the Code Snippet
The provided code snippet is structured as follows:
python
for i in range(5):
if i == 2:
break
print(i)
Code Execution Breakdown
- Loop Initialization: The loop iterates over a range of numbers from 0 to 4 (inclusive).
- Conditional Check: The condition `if i == 2:` checks if the current value of `i` is 2.
- Break Statement: If `i` is 2, the `break` statement is executed, which exits the loop immediately.
Step-by-Step Iteration
- Iteration 1:
- `i = 0`
- Condition: `0 == 2` (False)
- Action: Prints `0`
- Iteration 2:
- `i = 1`
- Condition: `1 == 2` (False)
- Action: Prints `1`
- Iteration 3:
- `i = 2`
- Condition: `2 == 2` (True)
- Action: Executes `break`, exiting the loop.
Final Output
- The printed output before the loop is terminated consists only of the values from the first two iterations.
- Therefore, the output is:
0
1
Conclusion
- The correct answer is option B: `0 1`.
- The loop halts before reaching the number 2, which is why the output does not include it or any subsequent numbers.
The provided code snippet is structured as follows:
python
for i in range(5):
if i == 2:
break
print(i)
Code Execution Breakdown
- Loop Initialization: The loop iterates over a range of numbers from 0 to 4 (inclusive).
- Conditional Check: The condition `if i == 2:` checks if the current value of `i` is 2.
- Break Statement: If `i` is 2, the `break` statement is executed, which exits the loop immediately.
Step-by-Step Iteration
- Iteration 1:
- `i = 0`
- Condition: `0 == 2` (False)
- Action: Prints `0`
- Iteration 2:
- `i = 1`
- Condition: `1 == 2` (False)
- Action: Prints `1`
- Iteration 3:
- `i = 2`
- Condition: `2 == 2` (True)
- Action: Executes `break`, exiting the loop.
Final Output
- The printed output before the loop is terminated consists only of the values from the first two iterations.
- Therefore, the output is:
0
1
Conclusion
- The correct answer is option B: `0 1`.
- The loop halts before reaching the number 2, which is why the output does not include it or any subsequent numbers.
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Community Answer
What is the output of the following code snippet?for i in range(5): i...
The loop iterates over the range of numbers from 0 to 4. When i equals 2, the break statement is executed, causing the loop to exit prematurely.
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What is the output of the following code snippet?for i in range(5): if i == 2: break print(i)a)0 1 2b)0 1c)0 1 3 4d)0 1 3Correct answer is option 'B'. Can you explain this answer?
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