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The perimeter of a triangle formed by 3i+4j+5k, 4i-3j-5k and 7i+j is
  • a)
    √450
  • b)
    √150
  • c)
    √50
  • d)
    √200
Correct answer is option 'A'. Can you explain this answer?
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The perimeter of a triangle formed by 3i+4j+5k, 4i-3j-5k and 7i+j isa)...
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The perimeter of a triangle formed by 3i+4j+5k, 4i-3j-5k and 7i+j isa)...
Understanding the Triangle Vertices
The vertices of the triangle are given as:
- A = 3i + 4j + 5k
- B = 4i - 3j - 5k
- C = 7i + j
Calculating Side Lengths
To find the perimeter of the triangle, we first need to calculate the lengths of its sides.
- Length of AB:
AB = |B - A|
= |(4i - 3j - 5k) - (3i + 4j + 5k)|
= |(4-3)i + (-3-4)j + (-5-5)k|
= |i - 7j - 10k|
= √(1^2 + (-7)^2 + (-10)^2)
= √(1 + 49 + 100)
= √150
- Length of BC:
BC = |C - B|
= |(7i + j) - (4i - 3j - 5k)|
= |(7-4)i + (1+3)j + (0+5)k|
= |3i + 4j + 5k|
= √(3^2 + 4^2 + 5^2)
= √(9 + 16 + 25)
= √50
- Length of CA:
CA = |A - C|
= |(3i + 4j + 5k) - (7i + j)|
= |(-4)i + (4-1)j + (5-0)k|
= |-4i + 3j + 5k|
= √((-4)^2 + 3^2 + 5^2)
= √(16 + 9 + 25)
= √50
Calculating the Perimeter
Now, the perimeter P of triangle ABC is:
P = AB + BC + CA
= √150 + √50 + √50
= √150 + 2√50
To find a common term, note that √50 = √(25×2) = 5√2:
P = √150 + 2(5√2)
= √150 + 10√2
However, we focus on simplifying this perimeter using the calculated values:
P = √150 + √50 + √50
= √150 + 2√50 = √150 + √200 = √450
Thus, the perimeter of the triangle is:
The Final Answer
The perimeter of the triangle is √450, which corresponds to option 'A'.
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The perimeter of a triangle formed by 3i+4j+5k, 4i-3j-5k and 7i+j isa)√450b)√150c)√50d)√200Correct answer is option 'A'. Can you explain this answer?
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