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The product of two numbers is 45 and their difference is 4. The sum of squares of the two numbers is
  • a)
    135
  • b)
    240
  • c)
    73
  • d)
    106
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
The product of two numbers is 45 and their difference is 4. The sum of...
As we know (a − b)2 = a2 + b2 − 2ab
We assume that first number is a and second number is b hence ab = 45
 and a - b = 4
after putting values we will get a2 + b= 106
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Community Answer
The product of two numbers is 45 and their difference is 4. The sum of...
To solve this problem, we can use a system of equations. Let's call the two numbers x and y.

Given:
The product of two numbers is 45.
xy = 45

Their difference is 4.
x - y = 4

We can solve this system of equations to find the values of x and y.

Solving for x in the second equation:
x = y + 4

Substituting this value of x into the first equation:
(y + 4)y = 45

Expanding and rearranging the equation:
y^2 + 4y - 45 = 0

Now we can factorize the quadratic equation:
(y + 9)(y - 5) = 0

Setting each factor equal to zero and solving for y:
y + 9 = 0 or y - 5 = 0

If y + 9 = 0, then y = -9
If y - 5 = 0, then y = 5

So we have two possible values for y: -9 and 5.

Substituting these values of y back into the equation x = y + 4 to find the corresponding values of x:
If y = -9, then x = -9 + 4 = -5
If y = 5, then x = 5 + 4 = 9

So the two numbers are -5 and 9.

Finding the sum of squares of the two numbers:
(-5)^2 + 9^2 = 25 + 81 = 106

Therefore, the sum of squares of the two numbers is 106, which corresponds to option 'D'.
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