A toy is in the shape of a right circular cylinder with a hemisphere o...
Radius of cylinder, hemiphere and cone = 5cm
Height osf cone = 12 cm
Then ⇒ (2×3.14×5×13) + (2×3.14×25) + (3.14×5×13)
⇒ 770 cm2
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A toy is in the shape of a right circular cylinder with a hemisphere o...
To find the surface area of the toy, we need to calculate the surface area of each component separately and then add them together.
1. Surface area of the cylindrical part:
The surface area of a cylinder is given by the formula 2πrh, where r is the radius and h is the height. In this case, the radius is 5 cm and the height is 13 cm. So, the surface area of the cylindrical part is:
A1 = 2π(5)(13) = 130π cm²
2. Surface area of the hemispherical part:
The surface area of a hemisphere is given by the formula 2πr². Since the radius is the same as the cylindrical part (5 cm), the surface area of the hemispherical part is:
A2 = 2π(5)² = 50π cm²
3. Surface area of the conical part:
The surface area of a cone is given by the formula πr(r + √(r² + h²)), where r is the radius and h is the height. In this case, the radius is 5 cm and the height is 12 cm. So, the surface area of the conical part is:
A3 = π(5)(5 + √(5² + 12²)) = π(5)(5 + √(25 + 144)) = π(5)(5 + √169) = 5π(5 + 13) = 90π cm²
4. Total surface area of the toy:
To find the total surface area, we add the surface areas of all the components together:
Total surface area = A1 + A2 + A3 = 130π + 50π + 90π = 270π cm²
Now, we need to determine the value of π to get the final answer in terms of a numeric value. π is approximately equal to 3.14. Therefore, the total surface area is approximately:
270π ≈ 270(3.14) ≈ 848.4 cm²
So, the correct answer is option D) 770 cm².
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