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Consider the following code snippet:
#include <iostream>
void changeArraySize(int** arr, int size) {
    *arr = new int[size];
}
int main() {
    int* arr = nullptr;
    changeArraySize(&arr, 5);
    std::cout << (arr != nullptr);
    delete[] arr;
    return 0;
}
What will be the output of the above code?
  • a)
    0
  • b)
    1
  • c)
    Error
  • d)
    Undefined behavior
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Consider the following code snippet:#include <iostream>void chan...
The 'changeArraySize' function receives a pointer to a pointer to 'int'. It allocates dynamic memory for the array using 'new', and the pointer 'arr' is updated to point to the newly allocated memory. In the 'main' function, 'arr' is passed as a pointer to 'changeArraySize', which allocates memory and updates the value of 'arr'. Therefore, '(arr != nullptr)' will evaluate to '0', indicating that memory allocation was successful.
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Community Answer
Consider the following code snippet:#include <iostream>void chan...
Explanation:

changeArraySize Function:
- The function `changeArraySize` takes a pointer to a pointer to an integer (`int**`) and an integer `size` as parameters.
- Inside the function, it dynamically allocates memory for an integer array of size `size` and assigns it to the pointer pointed to by `arr`.

main Function:
- In the `main` function, an integer pointer `arr` is initialized to `nullptr`.
- The `changeArraySize` function is called with the address of `arr` and a size of 5.
- After the function call, the output checks if `arr` is not equal to `nullptr` and prints the result.
- Finally, the memory allocated for `arr` is released using `delete[]`.

Output:
- The output of the code will be `0` because even though memory is allocated inside the `changeArraySize` function, the pointer `arr` is reassigned to the new memory address within the function scope.
- Therefore, outside the `changeArraySize` function, `arr` remains `nullptr` and the check `(arr != nullptr)` evaluates to false, resulting in the output of `0`.
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Consider the following code snippet:#include <iostream>void changeArraySize(int** arr, int size) { *arr = new int[size];}int main() { int* arr = nullptr; changeArraySize(&arr, 5); std::cout << (arr != nullptr); delete[] arr; return 0;}What will be the output of the above code?a)0b)1c)Errord)Undefined behaviorCorrect answer is option 'A'. Can you explain this answer?
Question Description
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