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The sum of the areas of a square and rectangle is 448 m square . if the length and breadth of the rectangle are 3 times and 2 times the side of the square respectively then?
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The sum of the areas of a square and rectangle is 448 m square . if t...
Solution:

Let's assume that the side of the square is 'x' meters.

Given that the length of the rectangle is 3 times the side of the square, and the breadth of the rectangle is 2 times the side of the square.

So, the length of the rectangle = 3x meters
And the breadth of the rectangle = 2x meters

The area of the square can be calculated by squaring the length of one side, which is given by x * x = x^2 square meters.

The area of the rectangle can be calculated by multiplying its length and breadth, which is given by (3x) * (2x) = 6x^2 square meters.

According to the problem, the sum of the areas of the square and rectangle is 448 square meters.

So, we can write the equation as:
x^2 + 6x^2 = 448

Simplifying the equation, we get:
7x^2 = 448

Dividing both sides of the equation by 7, we get:
x^2 = 64

Taking the square root of both sides, we get:
x = 8

Answer:
The side of the square is 8 meters.

To find the length and breadth of the rectangle, we can substitute the value of x in the equations:
Length of the rectangle = 3x = 3 * 8 = 24 meters
Breadth of the rectangle = 2x = 2 * 8 = 16 meters

Therefore, the length of the rectangle is 24 meters and the breadth of the rectangle is 16 meters.
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The sum of the areas of a square and rectangle is 448 m square . if the length and breadth of the rectangle are 3 times and 2 times the side of the square respectively then?
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