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5% of the population of a town were killed in an earthquake and 8 % of the remainder left the town now is 43700 , what was it's population at the beginning?
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5% of the population of a town were killed in an earthquake and 8 % of...
Given:
- 5% of the population of a town were killed in an earthquake.
- 8% of the remainder left the town.
- The current population is 43700.

To find:
- The population of the town at the beginning.

Assumptions:
- The earthquake and people leaving the town are the only factors affecting the population.
- The percentage calculations are based on the previous population number.

Step-by-step solution:

Step 1: Calculate the population after the earthquake.

Let's assume the initial population is 'P'.

- 5% of the population were killed in the earthquake, which means 95% of the population survived.
- Therefore, the population after the earthquake is 95% of the initial population: (95/100) * P.

Step 2: Calculate the population after people leaving the town.

- 8% of the remaining population left the town, which means 92% of the population stayed.
- Therefore, the population after people leaving the town is 92% of the population after the earthquake: (92/100) * (95/100) * P.

Step 3: Set up the equation.

According to the given information, the current population is 43700. So, we can write the equation as:

(92/100) * (95/100) * P = 43700

Step 4: Solve the equation.

To solve the equation, we can simplify the expression on the left-hand side and solve for P.

(92/100) * (95/100) * P = 43700

P = 43700 * (100/92) * (100/95)

P ≈ 51033.27

Answer:
The population of the town at the beginning was approximately 51033.
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5% of the population of a town were killed in an earthquake and 8 % of the remainder left the town now is 43700 , what was it's population at the beginning?
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