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A block R of mass 100 kg is placed on a block S of mass 150 kg as shown in the figure. Block R is tied to the wall by a massless and inextensible string PQ. If the coefficient of static friction for all surfaces is 0.4, the minimum force F (in kN) needed to move the block S is
  • a)
    0.69
  • b)
    0.88
  • c)
    0.98
  • d)
    1.37
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
A block R of mass 100 kg is placed on a block S of mass 150 kg as show...
Concept:
Making free body diagram of each block:
Balancing forces in positive x direction
∴ F = μRN1 + μRN2 = μ(RN1 + RN2)
where, RN1 = Normal reaction force on block R and  RN2 = Normal reaction force on block S
Calculation:
Given:
μ = 0.4
RN1 = 100g = 100 × 9.81 = 981 N
RN2 = (100 + 150)g = 250 × 9.81 = 2452.5 N
Minimum force (F) is
F = μ(RN1 + RN2)
F = 0.4 × (981 + 2452.5)  = 1373.4 N = 1.37 kN
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A block R of mass 100 kg is placed on a block S of mass 150 kg as shown in the figure. Block R is tied to the wall by a massless and inextensible string PQ. If the coefficient of staticfriction for all surfaces is 0.4, the minimum force F (in kN) needed to move the block S isa)0.69b)0.88c)0.98d)1.37Correct answer is option 'D'. Can you explain this answer?
Question Description
A block R of mass 100 kg is placed on a block S of mass 150 kg as shown in the figure. Block R is tied to the wall by a massless and inextensible string PQ. If the coefficient of staticfriction for all surfaces is 0.4, the minimum force F (in kN) needed to move the block S isa)0.69b)0.88c)0.98d)1.37Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A block R of mass 100 kg is placed on a block S of mass 150 kg as shown in the figure. Block R is tied to the wall by a massless and inextensible string PQ. If the coefficient of staticfriction for all surfaces is 0.4, the minimum force F (in kN) needed to move the block S isa)0.69b)0.88c)0.98d)1.37Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block R of mass 100 kg is placed on a block S of mass 150 kg as shown in the figure. Block R is tied to the wall by a massless and inextensible string PQ. If the coefficient of staticfriction for all surfaces is 0.4, the minimum force F (in kN) needed to move the block S isa)0.69b)0.88c)0.98d)1.37Correct answer is option 'D'. Can you explain this answer?.
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