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An equilateral prism of mass m rests on a rough horizontal surface with coefficient of friction miu . a horizontal force F is applied on the prism as shown in figure. If the coefficient of friction is sufficiently high so that the prism doesn't slide before toppling, then the minimum force required to topple the prism is?
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An equilateral prism of mass m rests on a rough horizontal surface wit...
The block's weight is W acting through its centre of gravity.
The normal force, Fn, from the surface will have the same magnitude as W.
The limiting frictional force will be Fr = μ.Fn = μW
In order to be raised and topple without slipping you imagine an initial position with the block's left edge just raised, so it is just starting to pivot on its right edge.
If it doesn't slip in this situation it can be tilted further without slipping.
In this position, resolving horizontally:
F = Fr
= μW
If the height of the block is h, then h = acos(30degree) = a√3/2
Taking moments about the right edge:
F*h = W*(a/2)
F * a√3/2 = Wa/2
F = W/√3
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An equilateral prism of mass m rests on a rough horizontal surface wit...
Introduction:

In this problem, we have an equilateral prism resting on a rough horizontal surface. We need to determine the minimum force required to topple the prism without it sliding. The prism has a mass of m and the coefficient of friction between the prism and the surface is given as μ.

Analysis:

To calculate the minimum force required to topple the prism, we need to consider the forces acting on it. There are two main forces involved:

1. The gravitational force acting downwards, which can be represented as Fg = mg, where m is the mass of the prism and g is the acceleration due to gravity (approximately 9.8 m/s²).

2. The frictional force acting horizontally, opposing the applied force. This force can be calculated using the equation Ff = μN, where N is the normal force.

Normal Force:

Before we can calculate the frictional force, we need to determine the normal force. The normal force is the force exerted by a surface to support the weight of an object resting on it. In this case, the normal force will be equal to the gravitational force acting downwards.

Frictional Force:

The frictional force is given by the equation Ff = μN, where Ff is the frictional force and μ is the coefficient of friction. In this case, the frictional force will act in the opposite direction to the applied force.

Conditions for Toppling:

To prevent the prism from sliding before toppling, the frictional force should be greater than or equal to the force component trying to slide the prism. This force component can be calculated as Fslide = F * sin(θ), where θ is the angle between the applied force and the horizontal surface.

Minimum Force for Toppling:

The minimum force required to topple the prism is the force at which the frictional force is equal to the force component trying to slide the prism. This can be expressed as Ff = Fslide.

Calculation:

Since Ff = μN and N = mg, we can substitute these values into the equation Ff = Fslide.

μmg = F * sin(θ)

Rearranging the equation, we can solve for the minimum force required to topple the prism:

F = μmg / sin(θ)

Conclusion:

In conclusion, the minimum force required to topple the prism without it sliding can be calculated using the equation F = μmg / sin(θ), where F is the force, μ is the coefficient of friction, m is the mass of the prism, g is the acceleration due to gravity, and θ is the angle between the applied force and the horizontal surface.
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An equilateral prism of mass m rests on a rough horizontal surface with coefficient of friction miu . a horizontal force F is applied on the prism as shown in figure. If the coefficient of friction is sufficiently high so that the prism doesn't slide before toppling, then the minimum force required to topple the prism is?
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An equilateral prism of mass m rests on a rough horizontal surface with coefficient of friction miu . a horizontal force F is applied on the prism as shown in figure. If the coefficient of friction is sufficiently high so that the prism doesn't slide before toppling, then the minimum force required to topple the prism is? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An equilateral prism of mass m rests on a rough horizontal surface with coefficient of friction miu . a horizontal force F is applied on the prism as shown in figure. If the coefficient of friction is sufficiently high so that the prism doesn't slide before toppling, then the minimum force required to topple the prism is? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An equilateral prism of mass m rests on a rough horizontal surface with coefficient of friction miu . a horizontal force F is applied on the prism as shown in figure. If the coefficient of friction is sufficiently high so that the prism doesn't slide before toppling, then the minimum force required to topple the prism is?.
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