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In a 110 V DC chopper drive using the CLC scheme, the maximum possible value of the accelerating current is 300 A. The lower limit of the current pulsation is 140 A. What is the maximum limit of current pulsation?
- a)140 A
- b)440 A
- c)160 A
- d)150 A
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
In a 110 V DC chopper drive using the CLC scheme, the maximum possible...
Current Limit Control of Chopper (CLC):
In this strategy, the chopper is turned on when the output current i0 equals a preset value I2.
The chopper is kept on till i0 increases to another preset value I1.
The chopper is turned off when i0 equals I1 and is kept off till the current i0 decays to I2.
The current i0 is thus limited to a maximum of I1 and a minimum of I2 as shown in Figure.
The chopping frequency and the pulse width are dependent on the load parameters.
The advantage of current limit control is that the ripple (I1 - I2), in the load current i0 can be adjusted to a small, predetermined value for a wide range of loads.
Application:
Given,
The maximum possible value of the accelerating current (I2) = 300 A
Current pulsation or current ripple (ΔI) = 140 A
The waveform can be drawn as,
From the waveform,
The maximum limit of current pulsation (I2) = I1 + ΔI = 300 + 140 = 440 A
In this strategy, the chopper is turned on when the output current i0 equals a preset value I2.
The chopper is kept on till i0 increases to another preset value I1.
The chopper is turned off when i0 equals I1 and is kept off till the current i0 decays to I2.
The current i0 is thus limited to a maximum of I1 and a minimum of I2 as shown in Figure.
The chopping frequency and the pulse width are dependent on the load parameters.
The advantage of current limit control is that the ripple (I1 - I2), in the load current i0 can be adjusted to a small, predetermined value for a wide range of loads.
Application:
Given,
The maximum possible value of the accelerating current (I2) = 300 A
Current pulsation or current ripple (ΔI) = 140 A
The waveform can be drawn as,
From the waveform,
The maximum limit of current pulsation (I2) = I1 + ΔI = 300 + 140 = 440 A
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In a 110 V DC chopper drive using the CLC scheme, the maximum possible...
Given:
Voltage supply (Vsupply) = 110 V
Maximum accelerating current (Imax) = 300 A
Lower limit of current pulsation (Imin) = 140 A
To find:
Maximum limit of current pulsation
Explanation:
In a chopper drive using the CLC (Current Limiting Control) scheme, the current is controlled by adjusting the duty cycle of the chopper. The duty cycle determines the average voltage applied to the load, which in turn controls the current. The control loop continuously monitors the current and adjusts the duty cycle to maintain it within a certain range.
The current pulsation (ΔI) is the difference between the maximum and minimum values of the current. It represents the ripple or variation in the current waveform. The maximum limit of current pulsation can be calculated by subtracting the lower limit of current pulsation from the maximum accelerating current.
Mathematically,
Maximum limit of current pulsation = Imax - Imin
Substituting the given values,
Maximum limit of current pulsation = 300 A - 140 A
Maximum limit of current pulsation = 160 A
Therefore, the maximum limit of current pulsation is 160 A. Option (c) is the correct answer.
Voltage supply (Vsupply) = 110 V
Maximum accelerating current (Imax) = 300 A
Lower limit of current pulsation (Imin) = 140 A
To find:
Maximum limit of current pulsation
Explanation:
In a chopper drive using the CLC (Current Limiting Control) scheme, the current is controlled by adjusting the duty cycle of the chopper. The duty cycle determines the average voltage applied to the load, which in turn controls the current. The control loop continuously monitors the current and adjusts the duty cycle to maintain it within a certain range.
The current pulsation (ΔI) is the difference between the maximum and minimum values of the current. It represents the ripple or variation in the current waveform. The maximum limit of current pulsation can be calculated by subtracting the lower limit of current pulsation from the maximum accelerating current.
Mathematically,
Maximum limit of current pulsation = Imax - Imin
Substituting the given values,
Maximum limit of current pulsation = 300 A - 140 A
Maximum limit of current pulsation = 160 A
Therefore, the maximum limit of current pulsation is 160 A. Option (c) is the correct answer.
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In a 110 V DC chopper drive using the CLC scheme, the maximum possible value of the accelerating current is 300 A. The lower limit of the current pulsation is 140 A. What is the maximum limit of current pulsation?a)140 Ab)440 Ac)160 Ad)150 ACorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2025 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about In a 110 V DC chopper drive using the CLC scheme, the maximum possible value of the accelerating current is 300 A. The lower limit of the current pulsation is 140 A. What is the maximum limit of current pulsation?a)140 Ab)440 Ac)160 Ad)150 ACorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a 110 V DC chopper drive using the CLC scheme, the maximum possible value of the accelerating current is 300 A. The lower limit of the current pulsation is 140 A. What is the maximum limit of current pulsation?a)140 Ab)440 Ac)160 Ad)150 ACorrect answer is option 'B'. Can you explain this answer?.
In a 110 V DC chopper drive using the CLC scheme, the maximum possible value of the accelerating current is 300 A. The lower limit of the current pulsation is 140 A. What is the maximum limit of current pulsation?a)140 Ab)440 Ac)160 Ad)150 ACorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2025 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about In a 110 V DC chopper drive using the CLC scheme, the maximum possible value of the accelerating current is 300 A. The lower limit of the current pulsation is 140 A. What is the maximum limit of current pulsation?a)140 Ab)440 Ac)160 Ad)150 ACorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a 110 V DC chopper drive using the CLC scheme, the maximum possible value of the accelerating current is 300 A. The lower limit of the current pulsation is 140 A. What is the maximum limit of current pulsation?a)140 Ab)440 Ac)160 Ad)150 ACorrect answer is option 'B'. Can you explain this answer?.
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