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How many EDTA (ethylenediaminetetraacetic acid) molecules are required to make an octahedral complex with a Ca2+
  • a)
    Six
  • b)
    Three
  • c)
    One
  • d)
    Two
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
How many EDTA (ethylenediaminetetraacetic acid) molecules are required...
EDTA, Which has four lone pair donor oxygen atoms and two lone pair donor nitrogen atoms in each molecule forms complex with Ca2+ ion. EDTA is hexa due to need 1 EDTA to form octahedral completes with ca+2
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How many EDTA (ethylenediaminetetraacetic acid) molecules are required...
To understand why the correct answer is option 'C', let's first discuss the structure of EDTA (ethylenediaminetetraacetic acid) and the coordination number of calcium ions.

Structure of EDTA:
EDTA is a hexadentate ligand, which means it can form six coordination bonds with a metal ion. It has four carboxylate groups (COO-) and two amine groups (NH2) that can act as donor atoms.

Coordination Number of Calcium Ions:
Calcium ions typically have a coordination number of 6, meaning they can form six coordinate bonds with ligands.

Octahedral Complex:
An octahedral complex is a type of coordination complex in which the metal ion is surrounded by six ligands arranged in an octahedral geometry. In this geometry, the ligands are located at the vertices of an octahedron.

Explanation:
For an octahedral complex with a calcium ion, six ligands are required to form six coordination bonds. Since EDTA is a hexadentate ligand capable of forming six coordination bonds, it can fully satisfy the coordination requirements of the calcium ion in an octahedral complex.

Therefore, the correct answer is option 'C' - One EDTA molecule is required to make an octahedral complex with a Ca2+ ion. This EDTA molecule will coordinate with the calcium ion through all six of its donor atoms, forming a stable octahedral complex.
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How many EDTA (ethylenediaminetetraacetic acid) molecules are required to make an octahedral complex with a Ca2+a)Sixb)Threec)Oned)TwoCorrect answer is option 'C'. Can you explain this answer?
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