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A filled vessel contains 3 parts of water and 5 parts of syrup. How much of the mixture must be drawn out and replaced with water, so that the mixture has 50% water and 50% syrup ?

  • a)
    1/5

  • b)
    1/6

  • c)
    1/4

  • d)
    1/3

  • e)
    1/2

Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A filled vessel contains 3 parts of water and 5 parts of syrup. How mu...
Given:
- The vessel contains 5 parts of water and 7 parts of syrup.
- The mixture needs to have 50% water and 50% syrup.

To find:
- How much of the mixture must be drawn out and replaced with water.

Approach:
1. Let's assume that the vessel initially contains a total of 12 parts (5 parts of water + 7 parts of syrup).
2. We need to remove a certain amount of this mixture and replace it with water.
3. Let's assume that x parts of the mixture are removed and replaced with water.
4. After removing x parts and replacing them with water, the amount of water in the mixture will remain the same (5 parts) but the amount of syrup will decrease by x parts.
5. As a result, the new mixture will contain (5 parts of water + 7 parts of syrup - x parts of syrup) = (5 parts of water + 7 - x parts of syrup).
6. According to the question, this new mixture needs to have an equal amount of water and syrup, i.e., (5 parts of water + 7 - x parts of syrup) = (5 parts of syrup + 5 parts of water).
7. Simplifying this equation, we get: 7 - x = 5.
8. Solving for x, we find that x = 2.

Answer:
- We need to draw out and replace 2 parts of the mixture with water.
- Therefore, the correct answer is option 'A' (1/7).
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Community Answer
A filled vessel contains 3 parts of water and 5 parts of syrup. How mu...
Given: A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. Explanation: 3 parts water and 5 parts syrup. So water = 3/8 and syrup = 5/8 To make them equal, 4/8 of water and syrup should be there Let x be the amount of liquid we replace by water, Water = 3x/8 and Syrup = 5x/8 Now, Water before replacement + 5x/8 = syrup before replacement – 5x/8 ⇒ syrup – water(before replacement) = 10x/8 = 5x/4 ⇒ 5/8 part – 3/8 part = 5x/4 ⇒ 1/4 part = 5x/4 ∴ 1/5 of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup.


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