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The height of a triangle is increased by 10%. To retain the original area of the triangle, its corresponding base must be decreased by:    (SSC Sub. Ins. 2015)
  • a)
  • b)
    10%
  • c)
    100/11%
  • d)
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The height of a triangle is increased by 10%. To retain the original a...
Let base = b, Height = h, 
So, Area = (b × h)/2So, Reduced base = [(½ b × h)/1.1h] × 2 = 10b/11
Percent reduction in base = [(b – 10b/11)/b] × 100
∴ Percent change in base = (100/11)%
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Community Answer
The height of a triangle is increased by 10%. To retain the original a...
Let base = b, Height = h, 
So, Area = (b × h)/2So, Reduced base = [(½ b × h)/1.1h] × 2 = 10b/11
Percent reduction in base = [(b – 10b/11)/b] × 100
∴ Percent change in base = (100/11)%
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The height of a triangle is increased by 10%. To retain the original area of the triangle, its corresponding base must be decreased by: (SSC Sub. Ins. 2015)a)b)10%c)100/11%d)Correct answer is option 'C'. Can you explain this answer?
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