Introduction:
CuSO4 is a chemical compound that consists of copper, sulfur, and oxygen. It is commonly known as copper sulfate or blue vitriol. In this response, we will discuss whether CuSO4 is a salt of a strong or weak acid and base.

Definition of Salt:
A salt is a compound that is formed by the reaction of an acid and a base. It consists of a positive ion from a base and a negative ion from an acid. The strength of an acid or a base determines whether the salt formed is a salt of a strong or weak acid and base.

Is CuSO4 a Salt of a Strong or Weak Acid and Base?
CuSO4 is a salt of a strong acid and a weak base. The acid in this case is sulfuric acid, which is a strong acid. The base is copper hydroxide, which is a weak base. When copper hydroxide reacts with sulfuric acid, CuSO4 is formed along with water.

Cu(OH)2 + H2SO4 → CuSO4 + 2H2O

Explanation:
Sulfuric acid is a strong acid because it completely dissociates into H+ and SO4^2- ions when dissolved in water. On the other hand, copper hydroxide is a weak base because it only partially dissociates into Cu2+ and OH- ions when dissolved in water.

Cu(OH)2 ↔ Cu2+ + 2OH-

When these two compounds react, the Cu2+ ion from copper hydroxide combines with the SO4^2- ion from sulfuric acid to form CuSO4. The remaining OH- ion from copper hydroxide combines with an H+ ion from sulfuric acid to form water.

Cu2+ + SO4^2- → CuSO4
OH- + H+ → H2O

Conclusion:
In conclusion, CuSO4 is a salt of a strong acid and a weak base. The acid in this case is sulfuric acid, which is a strong acid. The base is copper hydroxide, which is a weak base. When these two compounds react, CuSO4 is formed along with water.

Strong acid H2SO4 and weak base Cu(OH)2