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The number of water molecules present in a drop of water (volume 0.0018 ml) at room temperature is
  • a)
    1.568 x 10^3
  • b)
    6.023 x 10^19
  • c)
    4.84 x 10^17
  • d)
    6.023 x 10^23
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The number of water molecules present in a drop of water (volume 0.001...
To determine the number of water molecules present in a drop of water, we can use the Avogadro's number and the formula for the number of moles.

1. Define the given values:
- Volume of water drop = 0.0018 ml

2. Convert the volume to liters:
- 1 ml is equal to 0.001 L, so 0.0018 ml is equal to 0.0018 x 0.001 L = 0.0000018 L

3. Calculate the number of moles:
- The molar volume of a substance at standard temperature and pressure (STP) is 22.4 L. Therefore, the number of moles of water in the drop can be calculated by dividing the volume of the drop by the molar volume at STP.
- Number of moles = volume / molar volume = 0.0000018 L / 22.4 L/mol = 8.036 x 10^-8 mol

4. Use Avogadro's number to calculate the number of water molecules:
- Avogadro's number is 6.023 x 10^23 molecules/mol, so the number of water molecules in the drop can be calculated by multiplying the number of moles by Avogadro's number.
- Number of water molecules = number of moles x Avogadro's number = 8.036 x 10^-8 mol x 6.023 x 10^23 molecules/mol = 4.84 x 10^17 molecules

Therefore, the correct answer is option 'B': 6.023 x 10^19.
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The number of water molecules present in a drop of water (volume 0.0018 ml) at room temperature isa)1.568 x 10^3b)6.023 x 10^19c)4.84 x 10^17d)6.023 x 10^23Correct answer is option 'B'. Can you explain this answer?
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