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x2 + 20x + y2 + 16y = −20
The equation above defines a circle in the xy-plane. What are the coordinates of the center of the circle?
  • a)
    (−20, −16)
  • b)
    (−10, −8)
  • c)
    (10, 8)
  • d)
    (20, 16)
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
x2 + 20x + y2 + 16y = −20The equation above defines a circle in ...
The standard equation of a circle in the xy-plane is of the form (x − h)2 + (y − k)2 = r2, where (h, k) are the coordinates of the center of the circle and r is the radius. To convert the given equation to the standard form, complete the squares. The first two terms need a 100 to complete the square, and the second two terms need a 64. Adding 100 and 64 to both sides of the given equation yields (x2 + 20x + 100) + (y2 + 16y + 64) = −20 + 100 + 64, which  is equivalent to (x + 10)2 + (y + 8)2 = 144. Therefore, the coordinates of the center of the circle are (−10, −8).
Choice A is incorrect and is likely the result of not properly dividing when attempting to complete the square. Choice C is incorrect and is likely the result of making a sign error when evaluating the coordinates of the center. Choice D is incorrect and is likely the result of not properly dividing when attempting to complete the square and making a sign error when evaluating the coordinates of the center.
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Community Answer
x2 + 20x + y2 + 16y = −20The equation above defines a circle in ...
The given expression is:

x^2 + 20x + y^2 + 16y
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x2 + 20x + y2 + 16y = −20The equation above defines a circle in the xy-plane. What are the coordinates of the center of the circle?a)(−20, −16)b)(−10, −8)c)(10, 8)d)(20, 16)Correct answer is option 'B'. Can you explain this answer?
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