Question refer to the following information.The chart above shows approximations of the acceleration due to gravity in meters per second squaredfor the eight planets in our solar system. The weight of an object on a given planet can be found by using the formula W =mg , where W is the weight of the object measured in newtons, m is the mass of the object measured in kilograms, and g is the acceleration due to gravity on the planet measured in m/sec2.Q. An object on Earth has a weight of 150 newtons. On which planet would the same object have an approximate weight of 170 newtons?a)Venusb)Saturnc)Uranusd)NeptuneCorrect answer is option 'B'. Can you explain this answer?

EduRev

All Courses

Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity

Open App

SAT Exam > SAT Questions > Question refer to the following information.T...

Question refer to the following information.

The chart above shows approximations of the acceleration due to gravity in meters per second squared

for the eight planets in our solar system. The weight of an object on a given planet can be found by using the formula W =mg , where W is the weight of the object measured in newtons, m is the mass of the object measured in kilograms, and g is the acceleration due to gravity on the planet measured in m/sec².

Q. An object on Earth has a weight of 150 newtons. On which planet would the same object have an approximate weight of 170 newtons?

a)
Venus
b)
Saturn
c)
Uranus
d)
Neptune

Correct answer is option 'B'. Can you explain this answer?

Join for Free

Join for Free

Verified Answer

Question refer to the following information.The chart above shows appr...

Choice B is correct. On Earth, the acceleration due to gravity is 9.8 m/sec². Thus, for an object with a weight of 150 newtons, the formula W = mg becomes 150 = m(9.8), which shows that the mass of an object with a weight of 150 newtons on Earth is about 15.3 kilograms. Substituting this mass into the formula W = mg and now using the weight of 170 newtons gives 170 = 15.3g, which shows that the second planet’s acceleration due to gravity is about 11.1 m/sec². According to the table, this value for the acceleration due to gravity holds on Saturn.
Choices A, C, and D are incorrect. Using the formula W = mg and the values for g in the table shows that an object with a weight of 170 newtons on these planets would not have the same mass as an object with a weight of 150 newtons on Earth.

View all questions of this test

Most Upvoted Answer

Question refer to the following information.The chart above shows appr...

Answered by Orion Classes · View profile

Free Test

FREE

OneTime: Digital SAT Mock Test - 8
154 Ques | 180 Min

Start Free Test

View all free SAT tests

Community Answer

Question refer to the following information.The chart above shows appr...

View all answers Start learning for free

Explore Courses for SAT exam

Similar SAT Doubts

Question refer to the following information.The chart above shows approximations of the acceleration due to gravity in meters per second squaredfor the eight planets in our solar system. The weight of an object on a given planet can be found by using the formula W =mg , where W is the weight of the object measured in newtons, m is the mass of the object measured in kilograms, and g is the acceleration due to gravity on the planet measured in m/sec2.Q. What is the weight, in newtons, of an object on Mercury with a mass of 90 kilograms?

View answer

Question refer to the following information:An arrow is launched upward with an initial speed of 100 meters per second (m/s). The equations above describe the constant-acceleration motion of the arrow, where v0 is the initial speed of the arrow, v is the speed of the arrow as it is moving up in the air, h is the height of the arrow above the ground, t is the time elapsed since the arrow was projected upward, and g is the acceleration due to gravity (9.8 m/s2).What is the maximum height from the ground the arrow will rise to the nearest meter? Correct answer is '510'. Can you explain this answer?

View answer

Question refer to the following information.If shoppers enter a store at an average rate of r shoppers per minute and each stays in the store for an average time of T minutes, the average number of shoppers in the store, N, at any one time is given by the formula N = rT .This relationship is known as Little’s law.The owner of the Good Deals Store estimates that during business hours, an average of 3 shoppers per minute enter the store and that each of them stays an average of 15 minutes. The store owner uses Little’s law to estimate that there are 45 shoppers in the store at any time.Q. Little’s law can be applied to any part of the store, such as a particular department or the checkout lines. The store owner determines that, during business hours, approximately 84 shoppers per hour make a purchase and each of these shoppers spend an average of 5 minutes in the checkout line. At any time during business hours, about how many shoppers, on average, are waiting in the checkout line to make a purchase at the Good Deals Store? Correct answer is '7'. Can you explain this answer?

View answer

Question refer to the following information.One method of calculating the approximate age, in years, of a tree of a particular species is to multiply the diameter of the tree, in inches, by a constant called the growth factor for that species. The table above gives the growth factors for eight species of trees.If a white birch tree and a pin oak tree each now have a diameter of 1 foot, which of the following will be closest to the difference, in inches, of their diameters 10 years from now? (1 foot = 12 inches)

View answer

Question refer to the following information.The scatterplot above shows the densities of 7 planetoids, in grams per cubic centimeter, with respect to their average distances from the Sun in astronomical units (AU). The line of best fit is also shown.Q.An astronomer has discovered a new planetoid about 1.2 AU from the Sun. According to the line of best fit, which of the following best approximates the density of the planetoid, in grams per cubic centimeter?

View answer

Top Courses for SATView all

SAT Mock Test Series 2025

Mathematics for Digital SAT

Crash Course for Digital SAT

Reading and Writing for Digital SAT

Digital SAT Preparation Tutorials: Important Questions & Tricks

Top Courses for SAT

View all

Question refer to the following information.The chart above shows approximations of the acceleration due to gravity in meters per second squaredfor the eight planets in our solar system. The weight of an object on a given planet can be found by using the formula W =mg , where W is the weight of the object measured in newtons, m is the mass of the object measured in kilograms, and g is the acceleration due to gravity on the planet measured in m/sec2.Q. An object on Earth has a weight of 150 newtons. On which planet would the same object have an approximate weight of 170 newtons?a)Venusb)Saturnc)Uranusd)NeptuneCorrect answer is option 'B'. Can you explain this answer?

Share with a Friend

Answer this doubt

Question Description
Question refer to the following information.The chart above shows approximations of the acceleration due to gravity in meters per second squaredfor the eight planets in our solar system. The weight of an object on a given planet can be found by using the formula W =mg , where W is the weight of the object measured in newtons, m is the mass of the object measured in kilograms, and g is the acceleration due to gravity on the planet measured in m/sec2.Q. An object on Earth has a weight of 150 newtons. On which planet would the same object have an approximate weight of 170 newtons?a)Venusb)Saturnc)Uranusd)NeptuneCorrect answer is option 'B'. Can you explain this answer? for SAT 2025 is part of SAT preparation. The Question and answers have been prepared according to the SAT exam syllabus. Information about Question refer to the following information.The chart above shows approximations of the acceleration due to gravity in meters per second squaredfor the eight planets in our solar system. The weight of an object on a given planet can be found by using the formula W =mg , where W is the weight of the object measured in newtons, m is the mass of the object measured in kilograms, and g is the acceleration due to gravity on the planet measured in m/sec2.Q. An object on Earth has a weight of 150 newtons. On which planet would the same object have an approximate weight of 170 newtons?a)Venusb)Saturnc)Uranusd)NeptuneCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for SAT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Question refer to the following information.The chart above shows approximations of the acceleration due to gravity in meters per second squaredfor the eight planets in our solar system. The weight of an object on a given planet can be found by using the formula W =mg , where W is the weight of the object measured in newtons, m is the mass of the object measured in kilograms, and g is the acceleration due to gravity on the planet measured in m/sec2.Q. An object on Earth has a weight of 150 newtons. On which planet would the same object have an approximate weight of 170 newtons?a)Venusb)Saturnc)Uranusd)NeptuneCorrect answer is option 'B'. Can you explain this answer?.

Solutions for Question refer to the following information.The chart above shows approximations of the acceleration due to gravity in meters per second squaredfor the eight planets in our solar system. The weight of an object on a given planet can be found by using the formula W =mg , where W is the weight of the object measured in newtons, m is the mass of the object measured in kilograms, and g is the acceleration due to gravity on the planet measured in m/sec2.Q. An object on Earth has a weight of 150 newtons. On which planet would the same object have an approximate weight of 170 newtons?a)Venusb)Saturnc)Uranusd)NeptuneCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for SAT. Download more important topics, notes, lectures and mock test series for SAT Exam by signing up for free.

Here you can find the meaning of Question refer to the following information.The chart above shows approximations of the acceleration due to gravity in meters per second squaredfor the eight planets in our solar system. The weight of an object on a given planet can be found by using the formula W =mg , where W is the weight of the object measured in newtons, m is the mass of the object measured in kilograms, and g is the acceleration due to gravity on the planet measured in m/sec2.Q. An object on Earth has a weight of 150 newtons. On which planet would the same object have an approximate weight of 170 newtons?a)Venusb)Saturnc)Uranusd)NeptuneCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Question refer to the following information.The chart above shows approximations of the acceleration due to gravity in meters per second squaredfor the eight planets in our solar system. The weight of an object on a given planet can be found by using the formula W =mg , where W is the weight of the object measured in newtons, m is the mass of the object measured in kilograms, and g is the acceleration due to gravity on the planet measured in m/sec2.Q. An object on Earth has a weight of 150 newtons. On which planet would the same object have an approximate weight of 170 newtons?a)Venusb)Saturnc)Uranusd)NeptuneCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Question refer to the following information.The chart above shows approximations of the acceleration due to gravity in meters per second squaredfor the eight planets in our solar system. The weight of an object on a given planet can be found by using the formula W =mg , where W is the weight of the object measured in newtons, m is the mass of the object measured in kilograms, and g is the acceleration due to gravity on the planet measured in m/sec2.Q. An object on Earth has a weight of 150 newtons. On which planet would the same object have an approximate weight of 170 newtons?a)Venusb)Saturnc)Uranusd)NeptuneCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Question refer to the following information.The chart above shows approximations of the acceleration due to gravity in meters per second squaredfor the eight planets in our solar system. The weight of an object on a given planet can be found by using the formula W =mg , where W is the weight of the object measured in newtons, m is the mass of the object measured in kilograms, and g is the acceleration due to gravity on the planet measured in m/sec2.Q. An object on Earth has a weight of 150 newtons. On which planet would the same object have an approximate weight of 170 newtons?a)Venusb)Saturnc)Uranusd)NeptuneCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Question refer to the following information.The chart above shows approximations of the acceleration due to gravity in meters per second squaredfor the eight planets in our solar system. The weight of an object on a given planet can be found by using the formula W =mg , where W is the weight of the object measured in newtons, m is the mass of the object measured in kilograms, and g is the acceleration due to gravity on the planet measured in m/sec2.Q. An object on Earth has a weight of 150 newtons. On which planet would the same object have an approximate weight of 170 newtons?a)Venusb)Saturnc)Uranusd)NeptuneCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice SAT tests.

Explore Courses for SAT exam