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Of course of 5 Newton gives a mass M1 at acceleration of 10 m per second square and mass M2 and acceleration of 20 m per second square what exial would have give it both the basis but tired together?
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Of course of 5 Newton gives a mass M1 at acceleration of 10 m per seco...
Introduction:
In this question, we are given two masses, M1 and M2, and their respective accelerations, a1 and a2. We need to find the net force acting on the system when these masses are tied together.
Explanation:
To find the net force acting on the system, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.
Step 1: Calculate the force acting on M1:
- Mass of M1 = M1
- Acceleration of M1 = a1
- Force acting on M1 = M1 * a1
Step 2: Calculate the force acting on M2:
- Mass of M2 = M2
- Acceleration of M2 = a2
- Force acting on M2 = M2 * a2
Step 3: Calculate the net force acting on the system:
- The net force acting on the system is the sum of the individual forces acting on M1 and M2 when they are tied together.
- Net force = Force acting on M1 + Force acting on M2
Example:
Let's assume M1 = 2 kg, a1 = 10 m/s^2, M2 = 3 kg, and a2 = 20 m/s^2.
Step 1:
- Mass of M1 = 2 kg
- Acceleration of M1 = 10 m/s^2
- Force acting on M1 = 2 kg * 10 m/s^2 = 20 N
Step 2:
- Mass of M2 = 3 kg
- Acceleration of M2 = 20 m/s^2
- Force acting on M2 = 3 kg * 20 m/s^2 = 60 N
Step 3:
- Net force = Force acting on M1 + Force acting on M2
- Net force = 20 N + 60 N = 80 N
Therefore, when the masses M1 and M2 are tied together, the net force acting on the system is 80 N.
Conclusion:
In summary, to find the net force acting on a system of masses tied together, we need to calculate the individual forces acting on each mass using Newton's second law of motion and then add them together. In this specific example, the net force was found to be 80 N.
In this question, we are given two masses, M1 and M2, and their respective accelerations, a1 and a2. We need to find the net force acting on the system when these masses are tied together.
Explanation:
To find the net force acting on the system, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.
Step 1: Calculate the force acting on M1:
- Mass of M1 = M1
- Acceleration of M1 = a1
- Force acting on M1 = M1 * a1
Step 2: Calculate the force acting on M2:
- Mass of M2 = M2
- Acceleration of M2 = a2
- Force acting on M2 = M2 * a2
Step 3: Calculate the net force acting on the system:
- The net force acting on the system is the sum of the individual forces acting on M1 and M2 when they are tied together.
- Net force = Force acting on M1 + Force acting on M2
Example:
Let's assume M1 = 2 kg, a1 = 10 m/s^2, M2 = 3 kg, and a2 = 20 m/s^2.
Step 1:
- Mass of M1 = 2 kg
- Acceleration of M1 = 10 m/s^2
- Force acting on M1 = 2 kg * 10 m/s^2 = 20 N
Step 2:
- Mass of M2 = 3 kg
- Acceleration of M2 = 20 m/s^2
- Force acting on M2 = 3 kg * 20 m/s^2 = 60 N
Step 3:
- Net force = Force acting on M1 + Force acting on M2
- Net force = 20 N + 60 N = 80 N
Therefore, when the masses M1 and M2 are tied together, the net force acting on the system is 80 N.
Conclusion:
In summary, to find the net force acting on a system of masses tied together, we need to calculate the individual forces acting on each mass using Newton's second law of motion and then add them together. In this specific example, the net force was found to be 80 N.
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Of course of 5 Newton gives a mass M1 at acceleration of 10 m per second square and mass M2 and acceleration of 20 m per second square what exial would have give it both the basis but tired together?
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Of course of 5 Newton gives a mass M1 at acceleration of 10 m per second square and mass M2 and acceleration of 20 m per second square what exial would have give it both the basis but tired together? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about Of course of 5 Newton gives a mass M1 at acceleration of 10 m per second square and mass M2 and acceleration of 20 m per second square what exial would have give it both the basis but tired together? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Of course of 5 Newton gives a mass M1 at acceleration of 10 m per second square and mass M2 and acceleration of 20 m per second square what exial would have give it both the basis but tired together?.
Of course of 5 Newton gives a mass M1 at acceleration of 10 m per second square and mass M2 and acceleration of 20 m per second square what exial would have give it both the basis but tired together? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about Of course of 5 Newton gives a mass M1 at acceleration of 10 m per second square and mass M2 and acceleration of 20 m per second square what exial would have give it both the basis but tired together? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Of course of 5 Newton gives a mass M1 at acceleration of 10 m per second square and mass M2 and acceleration of 20 m per second square what exial would have give it both the basis but tired together?.
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