Simplify the following Boolean expression.E(E + F) + DE + D(E + F)a)D ...
To simplify the given Boolean expression, let's break it down step by step:
Step 1: Simplify the expression E(E F)
- In this expression, E is being multiplied by (E F).
- According to the distributive property of Boolean algebra, E(E F) is equivalent to EE EF.
- Since E is being multiplied by itself (EE), it simplifies to just E.
- Thus, the expression E(E F) simplifies to E EF.
Step 2: Simplify the expression DE
- In this expression, D is being multiplied by E.
- Since there are no common variables in this expression, it cannot be simplified further.
Step 3: Simplify the expression D(E F)
- In this expression, D is being multiplied by (E F).
- According to the distributive property of Boolean algebra, D(E F) is equivalent to DE DF.
- Since we have already simplified DE in Step 2, the expression D(E F) simplifies to E DF.
Step 4: Simplify the expression E DF
- In this expression, E is being multiplied by DF.
- Since there are no common variables in this expression, it cannot be simplified further.
Step 5: Combine the simplified expressions from Steps 1, 2, and 4
- The simplified expressions from Steps 1, 2, and 4 are: E EF, DE, and E DF, respectively.
- Combining these expressions, we get: (E EF) DE (E DF).
Step 6: Further simplify the expression (E EF) DE (E DF)
- In this expression, we have three terms: (E EF), DE, and (E DF).
- Since there are no common variables among these terms, we cannot simplify the expression any further.
Therefore, the simplified Boolean expression is E DF, which corresponds to option 'C'.
Simplify the following Boolean expression.E(E + F) + DE + D(E + F)a)D ...
E(E + F) + DE + D(E + F)
=E.E + E.F + D.E + D.E + D.F
=E + E.F + D.E + D.F
=E (1+F) + D.E + D.F As per Annulment Law : 1 + A = 1
=E + D.E + D.F As per Identity Law : A.1 = A
=E(1+D) + D.F
=E + D.F ( Answer )
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