Chemistry Exam > Chemistry Questions > Select the best reducing agent or method — ca...
Start Learning for Free
Select the best reducing agent or method — carbon; none needed (occur native); a more active metal; electrolysis — for the industrial preparation for each of the following elements: (a) Pt, (b) Na, (c) Os, (d) Co, (e) Li, (f) Zr?
Most Upvoted Answer
Select the best reducing agent or method — carbon; none needed (occur ...
Industrial Preparation of Elements using Reducing Agents or Methods
In industrial processes, various reducing agents or methods are employed to prepare different elements. The choice of reducing agent or method depends on the reactivity of the element and the desired conditions for the reaction. Let's explore the best reducing agent or method for the industrial preparation of each of the following elements:
(a) Platinum (Pt)
- Best Reducing Agent or Method: Carbon
- Explanation: Platinum occurs natively in the Earth's crust and is found in the form of platinum nuggets or grains. Therefore, no reducing agent is needed for its industrial preparation.
(b) Sodium (Na)
- Best Reducing Agent or Method: None needed (occur native)
- Explanation: Sodium is a highly reactive metal that occurs natively in nature. It is found in various minerals such as halite (NaCl), soda ash (Na2CO3), and cryolite (Na3AlF6). Therefore, no reducing agent is required for the industrial preparation of sodium.
(c) Osmium (Os)
- Best Reducing Agent or Method: A more active metal
- Explanation: Osmium is a transition metal that is not found in its pure form in nature. It is commonly obtained as a byproduct from the processing of platinum ores. To isolate osmium, a more active metal such as zinc or magnesium is used as a reducing agent. The reducing agent reacts with osmium compounds, such as osmium tetroxide (OsO4), to form osmium metal.
(d) Cobalt (Co)
- Best Reducing Agent or Method: A more active metal
- Explanation: Cobalt is a transition metal that is primarily obtained as a byproduct of nickel and copper mining. It is usually found in the form of cobalt sulfide or arsenide minerals. To extract cobalt, a more active metal like magnesium or aluminum is used as a reducing agent. The reducing agent reacts with cobalt compounds to form cobalt metal.
(e) Lithium (Li)
- Best Reducing Agent or Method: Electrolysis
- Explanation: Lithium is a highly reactive metal that is not found in its pure form in nature. It is commonly obtained from lithium-containing minerals such as spodumene (LiAl(SiO3)2) or lithium chloride (LiCl). The industrial preparation of lithium involves the use of electrolysis. Lithium salts are dissolved in a solvent, and an electric current is passed through the solution. The lithium ions are reduced at the cathode, forming pure lithium metal.
(f) Zirconium (Zr)
- Best Reducing Agent or Method: A more active metal
- Explanation: Zirconium is a transition metal that is commonly found in the form of zirconium silicate (ZrSiO4) or zirconium dioxide (ZrO2). To obtain zirconium metal, a more active metal such as magnesium or sodium is used as a reducing agent. The reducing agent reacts with zirconium compounds, such as zirconium chloride (ZrCl4), to form zirconium metal.
In summary, the choice of reducing agent or method for the industrial preparation of elements depends on their reactivity and availability in nature. Some elements occur natively and do
In industrial processes, various reducing agents or methods are employed to prepare different elements. The choice of reducing agent or method depends on the reactivity of the element and the desired conditions for the reaction. Let's explore the best reducing agent or method for the industrial preparation of each of the following elements:
(a) Platinum (Pt)
- Best Reducing Agent or Method: Carbon
- Explanation: Platinum occurs natively in the Earth's crust and is found in the form of platinum nuggets or grains. Therefore, no reducing agent is needed for its industrial preparation.
(b) Sodium (Na)
- Best Reducing Agent or Method: None needed (occur native)
- Explanation: Sodium is a highly reactive metal that occurs natively in nature. It is found in various minerals such as halite (NaCl), soda ash (Na2CO3), and cryolite (Na3AlF6). Therefore, no reducing agent is required for the industrial preparation of sodium.
(c) Osmium (Os)
- Best Reducing Agent or Method: A more active metal
- Explanation: Osmium is a transition metal that is not found in its pure form in nature. It is commonly obtained as a byproduct from the processing of platinum ores. To isolate osmium, a more active metal such as zinc or magnesium is used as a reducing agent. The reducing agent reacts with osmium compounds, such as osmium tetroxide (OsO4), to form osmium metal.
(d) Cobalt (Co)
- Best Reducing Agent or Method: A more active metal
- Explanation: Cobalt is a transition metal that is primarily obtained as a byproduct of nickel and copper mining. It is usually found in the form of cobalt sulfide or arsenide minerals. To extract cobalt, a more active metal like magnesium or aluminum is used as a reducing agent. The reducing agent reacts with cobalt compounds to form cobalt metal.
(e) Lithium (Li)
- Best Reducing Agent or Method: Electrolysis
- Explanation: Lithium is a highly reactive metal that is not found in its pure form in nature. It is commonly obtained from lithium-containing minerals such as spodumene (LiAl(SiO3)2) or lithium chloride (LiCl). The industrial preparation of lithium involves the use of electrolysis. Lithium salts are dissolved in a solvent, and an electric current is passed through the solution. The lithium ions are reduced at the cathode, forming pure lithium metal.
(f) Zirconium (Zr)
- Best Reducing Agent or Method: A more active metal
- Explanation: Zirconium is a transition metal that is commonly found in the form of zirconium silicate (ZrSiO4) or zirconium dioxide (ZrO2). To obtain zirconium metal, a more active metal such as magnesium or sodium is used as a reducing agent. The reducing agent reacts with zirconium compounds, such as zirconium chloride (ZrCl4), to form zirconium metal.
In summary, the choice of reducing agent or method for the industrial preparation of elements depends on their reactivity and availability in nature. Some elements occur natively and do
Community Answer
Select the best reducing agent or method — carbon; none needed (occur ...
Industrial Preparation of Elements
In industrial processes, various reducing agents or methods are used to prepare different elements. The choice of reducing agent or method depends on the reactivity of the element being prepared. Let's discuss the best reducing agent or method for the industrial preparation of each of the following elements:
(a) Platinum (Pt):
- Carbon: Carbon can be used as a reducing agent to prepare platinum from its ore, platinum sulfide (PtS2). The reaction can be represented as follows:
PtS2 + 2C → Pt + 2CS₂
(b) Sodium (Na):
- None needed (occur native): Sodium is a highly reactive metal and occurs naturally in its elemental form. Therefore, no reducing agent or method is required for its industrial preparation.
(c) Osmium (Os):
- A more active metal: Osmium is a less reactive metal and can be prepared by using a more active metal, such as aluminum or magnesium, as a reducing agent. The reaction can be represented as follows:
OsO₄ + 4Al → 4AlO + Os
(d) Cobalt (Co):
- Carbon: Carbon can be used as a reducing agent to prepare cobalt from its ore, cobalt oxide (Co₃O₄). The reaction can be represented as follows:
Co₃O₄ + 4C → 3Co + 4CO
(e) Lithium (Li):
- Electrolysis: Lithium is a highly reactive metal and cannot be prepared by using a reducing agent. Instead, it is prepared by the electrolysis of lithium chloride (LiCl) or lithium hydroxide (LiOH) in the presence of a suitable solvent. The reaction can be represented as follows:
2LiCl (or LiOH) → 2Li + Cl₂ (or H₂O)
(f) Zirconium (Zr):
- A more active metal: Zirconium is a less reactive metal and can be prepared by using a more active metal, such as magnesium, as a reducing agent. The reaction can be represented as follows:
ZrO₂ + 2Mg → 2MgO + Zr
Summary:
- Carbon can be used as a reducing agent for the industrial preparation of platinum and cobalt.
- Sodium occurs naturally in its elemental form, so no reducing agent or method is needed.
- Osmium can be prepared by using a more active metal, such as aluminum or magnesium, as a reducing agent.
- Lithium is prepared by electrolysis of lithium chloride or lithium hydroxide.
- Zirconium can be prepared by using a more active metal, such as magnesium, as a reducing agent.
It is important to choose the appropriate reducing agent or method for the industrial preparation of each element based on their reactivity and availability.
In industrial processes, various reducing agents or methods are used to prepare different elements. The choice of reducing agent or method depends on the reactivity of the element being prepared. Let's discuss the best reducing agent or method for the industrial preparation of each of the following elements:
(a) Platinum (Pt):
- Carbon: Carbon can be used as a reducing agent to prepare platinum from its ore, platinum sulfide (PtS2). The reaction can be represented as follows:
PtS2 + 2C → Pt + 2CS₂
(b) Sodium (Na):
- None needed (occur native): Sodium is a highly reactive metal and occurs naturally in its elemental form. Therefore, no reducing agent or method is required for its industrial preparation.
(c) Osmium (Os):
- A more active metal: Osmium is a less reactive metal and can be prepared by using a more active metal, such as aluminum or magnesium, as a reducing agent. The reaction can be represented as follows:
OsO₄ + 4Al → 4AlO + Os
(d) Cobalt (Co):
- Carbon: Carbon can be used as a reducing agent to prepare cobalt from its ore, cobalt oxide (Co₃O₄). The reaction can be represented as follows:
Co₃O₄ + 4C → 3Co + 4CO
(e) Lithium (Li):
- Electrolysis: Lithium is a highly reactive metal and cannot be prepared by using a reducing agent. Instead, it is prepared by the electrolysis of lithium chloride (LiCl) or lithium hydroxide (LiOH) in the presence of a suitable solvent. The reaction can be represented as follows:
2LiCl (or LiOH) → 2Li + Cl₂ (or H₂O)
(f) Zirconium (Zr):
- A more active metal: Zirconium is a less reactive metal and can be prepared by using a more active metal, such as magnesium, as a reducing agent. The reaction can be represented as follows:
ZrO₂ + 2Mg → 2MgO + Zr
Summary:
- Carbon can be used as a reducing agent for the industrial preparation of platinum and cobalt.
- Sodium occurs naturally in its elemental form, so no reducing agent or method is needed.
- Osmium can be prepared by using a more active metal, such as aluminum or magnesium, as a reducing agent.
- Lithium is prepared by electrolysis of lithium chloride or lithium hydroxide.
- Zirconium can be prepared by using a more active metal, such as magnesium, as a reducing agent.
It is important to choose the appropriate reducing agent or method for the industrial preparation of each element based on their reactivity and availability.
|
Explore Courses for Chemistry exam
|
|
Similar Chemistry Doubts
Select the best reducing agent or method — carbon; none needed (occur native); a more active metal; electrolysis — for the industrial preparation for each of the following elements: (a) Pt, (b) Na, (c) Os, (d) Co, (e) Li, (f) Zr?
Question Description
Select the best reducing agent or method — carbon; none needed (occur native); a more active metal; electrolysis — for the industrial preparation for each of the following elements: (a) Pt, (b) Na, (c) Os, (d) Co, (e) Li, (f) Zr? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Select the best reducing agent or method — carbon; none needed (occur native); a more active metal; electrolysis — for the industrial preparation for each of the following elements: (a) Pt, (b) Na, (c) Os, (d) Co, (e) Li, (f) Zr? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Select the best reducing agent or method — carbon; none needed (occur native); a more active metal; electrolysis — for the industrial preparation for each of the following elements: (a) Pt, (b) Na, (c) Os, (d) Co, (e) Li, (f) Zr?.
Select the best reducing agent or method — carbon; none needed (occur native); a more active metal; electrolysis — for the industrial preparation for each of the following elements: (a) Pt, (b) Na, (c) Os, (d) Co, (e) Li, (f) Zr? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Select the best reducing agent or method — carbon; none needed (occur native); a more active metal; electrolysis — for the industrial preparation for each of the following elements: (a) Pt, (b) Na, (c) Os, (d) Co, (e) Li, (f) Zr? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Select the best reducing agent or method — carbon; none needed (occur native); a more active metal; electrolysis — for the industrial preparation for each of the following elements: (a) Pt, (b) Na, (c) Os, (d) Co, (e) Li, (f) Zr?.
Solutions for Select the best reducing agent or method — carbon; none needed (occur native); a more active metal; electrolysis — for the industrial preparation for each of the following elements: (a) Pt, (b) Na, (c) Os, (d) Co, (e) Li, (f) Zr? in English & in Hindi are available as part of our courses for Chemistry.
Download more important topics, notes, lectures and mock test series for Chemistry Exam by signing up for free.
Here you can find the meaning of Select the best reducing agent or method — carbon; none needed (occur native); a more active metal; electrolysis — for the industrial preparation for each of the following elements: (a) Pt, (b) Na, (c) Os, (d) Co, (e) Li, (f) Zr? defined & explained in the simplest way possible. Besides giving the explanation of
Select the best reducing agent or method — carbon; none needed (occur native); a more active metal; electrolysis — for the industrial preparation for each of the following elements: (a) Pt, (b) Na, (c) Os, (d) Co, (e) Li, (f) Zr?, a detailed solution for Select the best reducing agent or method — carbon; none needed (occur native); a more active metal; electrolysis — for the industrial preparation for each of the following elements: (a) Pt, (b) Na, (c) Os, (d) Co, (e) Li, (f) Zr? has been provided alongside types of Select the best reducing agent or method — carbon; none needed (occur native); a more active metal; electrolysis — for the industrial preparation for each of the following elements: (a) Pt, (b) Na, (c) Os, (d) Co, (e) Li, (f) Zr? theory, EduRev gives you an
ample number of questions to practice Select the best reducing agent or method — carbon; none needed (occur native); a more active metal; electrolysis — for the industrial preparation for each of the following elements: (a) Pt, (b) Na, (c) Os, (d) Co, (e) Li, (f) Zr? tests, examples and also practice Chemistry tests.
|
|
Explore Courses for Chemistry exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup