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Two ants start simultaneously from two ant holes towards each other. The first ant coveres 8% of the distance between the two ant holes in 3 hours, the second ant covered 7/120 of the distance in 2 hours 30 minutes. Find the speed (feet/h) of the second ant if the first ant travelled 800 feet to the meeting point.a)15 feet/hb)25 feet/hc)45 feet/hd)35 feet/hCorrect answer is option 'D'. Can you explain this answer?
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Two ants start simultaneously from two ant holes towards each other. T...
Let's assume that the distance between the two ant holes is D feet.
We are given that the first ant covers 8% of the distance in 3 hours. This means that it covers 0.08D distance in 3 hours. We can calculate the speed of the first ant using the formula: Speed = Distance/Time. Therefore, the speed of the first ant is (0.08D)/3 feet per hour.
Similarly, we are given that the second ant covers 7/120 of the distance in 2 hours 30 minutes. This means that it covers (7/120)D distance in 2.5 hours. We can calculate the speed of the second ant using the formula: Speed = Distance/Time. Therefore, the speed of the second ant is ((7/120)D)/(2.5) feet per hour.
We know that when the two ants meet, they would have covered the entire distance between the ant holes, which is D. We are given that the first ant travels 800 feet to the meeting point. This means that the second ant would have traveled D - 800 feet to the meeting point.
We can now set up an equation using the speed-distance-time formula for both ants:
Speed of first ant * Time taken by first ant = Distance traveled by first ant
Speed of second ant * Time taken by second ant = Distance traveled by second ant
Since the time taken by both ants is the same (since they start simultaneously and meet at the same time), we can equate the two equations:
(0.08D)/3 * T = 800
((7/120)D)/(2.5) * T = D - 800
Simplifying the equations, we get:
(0.08D)/3 * T = 800
(7/120)(2.5) * T = D - 800
We can solve these equations to find the value of D and T, but that is not required to find the speed of the second ant. We can substitute the value of D - 800 from the second equation into the first equation and solve for the speed of the second ant:
(7/120)(2.5) * T = D - 800
(7/120)(2.5) * T = 120 - 800
(7/120)(2.5) * T = 320
Simplifying further, we get:
(7/120)(2.5) * T = 320
(7/48) * T = 320
T = (48/7) * 320
T = 3200/7
Now, we can substitute the value of T into the second equation to find the speed of the second ant:
(7/120)D/(2.5) * (3200/7) = D - 800
Simplifying further, we get:
(7/120)D/(2.5) * (3200/7) = D - 800
(7/120)(3200/2.5) = D - 800
(7/120)(1280) = D - 800
8960/120 = D - 800
74.67 = D - 800
D = 874.67
Therefore, the speed of the second ant is ((7/120)(874.67
We are given that the first ant covers 8% of the distance in 3 hours. This means that it covers 0.08D distance in 3 hours. We can calculate the speed of the first ant using the formula: Speed = Distance/Time. Therefore, the speed of the first ant is (0.08D)/3 feet per hour.
Similarly, we are given that the second ant covers 7/120 of the distance in 2 hours 30 minutes. This means that it covers (7/120)D distance in 2.5 hours. We can calculate the speed of the second ant using the formula: Speed = Distance/Time. Therefore, the speed of the second ant is ((7/120)D)/(2.5) feet per hour.
We know that when the two ants meet, they would have covered the entire distance between the ant holes, which is D. We are given that the first ant travels 800 feet to the meeting point. This means that the second ant would have traveled D - 800 feet to the meeting point.
We can now set up an equation using the speed-distance-time formula for both ants:
Speed of first ant * Time taken by first ant = Distance traveled by first ant
Speed of second ant * Time taken by second ant = Distance traveled by second ant
Since the time taken by both ants is the same (since they start simultaneously and meet at the same time), we can equate the two equations:
(0.08D)/3 * T = 800
((7/120)D)/(2.5) * T = D - 800
Simplifying the equations, we get:
(0.08D)/3 * T = 800
(7/120)(2.5) * T = D - 800
We can solve these equations to find the value of D and T, but that is not required to find the speed of the second ant. We can substitute the value of D - 800 from the second equation into the first equation and solve for the speed of the second ant:
(7/120)(2.5) * T = D - 800
(7/120)(2.5) * T = 120 - 800
(7/120)(2.5) * T = 320
Simplifying further, we get:
(7/120)(2.5) * T = 320
(7/48) * T = 320
T = (48/7) * 320
T = 3200/7
Now, we can substitute the value of T into the second equation to find the speed of the second ant:
(7/120)D/(2.5) * (3200/7) = D - 800
Simplifying further, we get:
(7/120)D/(2.5) * (3200/7) = D - 800
(7/120)(3200/2.5) = D - 800
(7/120)(1280) = D - 800
8960/120 = D - 800
74.67 = D - 800
D = 874.67
Therefore, the speed of the second ant is ((7/120)(874.67
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Two ants start simultaneously from two ant holes towards each other. The first ant coveres 8% of the distance between the two ant holes in 3 hours, the second ant covered 7/120 of the distance in 2 hours 30 minutes. Find the speed (feet/h) of the second ant if the first ant travelled 800 feet to the meeting point.a)15 feet/hb)25 feet/hc)45 feet/hd)35 feet/hCorrect answer is option 'D'. Can you explain this answer?
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Two ants start simultaneously from two ant holes towards each other. The first ant coveres 8% of the distance between the two ant holes in 3 hours, the second ant covered 7/120 of the distance in 2 hours 30 minutes. Find the speed (feet/h) of the second ant if the first ant travelled 800 feet to the meeting point.a)15 feet/hb)25 feet/hc)45 feet/hd)35 feet/hCorrect answer is option 'D'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about Two ants start simultaneously from two ant holes towards each other. The first ant coveres 8% of the distance between the two ant holes in 3 hours, the second ant covered 7/120 of the distance in 2 hours 30 minutes. Find the speed (feet/h) of the second ant if the first ant travelled 800 feet to the meeting point.a)15 feet/hb)25 feet/hc)45 feet/hd)35 feet/hCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two ants start simultaneously from two ant holes towards each other. The first ant coveres 8% of the distance between the two ant holes in 3 hours, the second ant covered 7/120 of the distance in 2 hours 30 minutes. Find the speed (feet/h) of the second ant if the first ant travelled 800 feet to the meeting point.a)15 feet/hb)25 feet/hc)45 feet/hd)35 feet/hCorrect answer is option 'D'. Can you explain this answer?.
Two ants start simultaneously from two ant holes towards each other. The first ant coveres 8% of the distance between the two ant holes in 3 hours, the second ant covered 7/120 of the distance in 2 hours 30 minutes. Find the speed (feet/h) of the second ant if the first ant travelled 800 feet to the meeting point.a)15 feet/hb)25 feet/hc)45 feet/hd)35 feet/hCorrect answer is option 'D'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about Two ants start simultaneously from two ant holes towards each other. The first ant coveres 8% of the distance between the two ant holes in 3 hours, the second ant covered 7/120 of the distance in 2 hours 30 minutes. Find the speed (feet/h) of the second ant if the first ant travelled 800 feet to the meeting point.a)15 feet/hb)25 feet/hc)45 feet/hd)35 feet/hCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two ants start simultaneously from two ant holes towards each other. The first ant coveres 8% of the distance between the two ant holes in 3 hours, the second ant covered 7/120 of the distance in 2 hours 30 minutes. Find the speed (feet/h) of the second ant if the first ant travelled 800 feet to the meeting point.a)15 feet/hb)25 feet/hc)45 feet/hd)35 feet/hCorrect answer is option 'D'. Can you explain this answer?.
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