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The soil strata consisted of sand-extending up to great depth.The water table was found to be at the ground surface. The soil parameters Ysat= 20kn/m^3 and phi=32.Find the effective strength at a depth of 6 m from the ground surface. Take Yw=10 kN/m3 ANS 49 kN/m^2 � . e 3 d "' _ 32�. Find the - 20 kN/m -an "' - � - be at the ground surface. The soil parameters_ Ysat - = 10 kN/m3] effective strength at a depth of 6 m from the ground surface?
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The soil strata consisted of sand-extending up to great depth.The wate...
Effective Strength at a Depth of 6m from the Ground Surface
Given Data:
- Soil strata: Sand
- Depth of soil strata: Great depth
- Water table: At the ground surface
- Soil parameters:
- Ysat = 20 kN/m^3
- φ = 32
- Yw = 10 kN/m^3
To determine the effective strength at a depth of 6m from the ground surface, we need to consider the effective stress and the shear strength parameters of the soil.
1. Effective Stress:
The effective stress (σ') is the difference between the total stress (σ) and the pore water pressure (u). It is given by the equation:
σ' = σ - u
In this case, as the water table is at the ground surface, the pore water pressure at any depth in the soil can be assumed to be equal to the unit weight of water times the depth. Therefore, the pore water pressure (u) at a depth of 6m is given by:
u = Yw * h
= 10 kN/m^3 * 6m
= 60 kN/m^2
2. Shear Strength Parameters:
The shear strength of the soil depends on the angle of internal friction (φ) and the cohesion (c) of the soil.
In this case, the soil is described as sand with an angle of internal friction (φ) of 32°. As sand is a cohesionless soil, the cohesion (c) is assumed to be zero.
3. Effective Strength:
The effective strength (τ') of the soil can be calculated using the Mohr-Coulomb shear strength equation:
τ' = c' + σ' * tan(φ')
For cohesionless soils, the effective strength equation simplifies to:
τ' = σ' * tan(φ')
In this case, the effective strength at a depth of 6m can be calculated as follows:
τ' = σ' * tan(φ')
= (Ysat - Yw) * tan(φ') [Since c' = 0]
Substituting the given values:
τ' = (20 kN/m^3 - 10 kN/m^3) * tan(32°)
= 10 kN/m^3 * tan(32°)
Using a calculator, we can determine:
τ' ≈ 5.91 kN/m^2
Therefore, the effective strength at a depth of 6m from the ground surface is approximately 5.91 kN/m^2.
Given Data:
- Soil strata: Sand
- Depth of soil strata: Great depth
- Water table: At the ground surface
- Soil parameters:
- Ysat = 20 kN/m^3
- φ = 32
- Yw = 10 kN/m^3
To determine the effective strength at a depth of 6m from the ground surface, we need to consider the effective stress and the shear strength parameters of the soil.
1. Effective Stress:
The effective stress (σ') is the difference between the total stress (σ) and the pore water pressure (u). It is given by the equation:
σ' = σ - u
In this case, as the water table is at the ground surface, the pore water pressure at any depth in the soil can be assumed to be equal to the unit weight of water times the depth. Therefore, the pore water pressure (u) at a depth of 6m is given by:
u = Yw * h
= 10 kN/m^3 * 6m
= 60 kN/m^2
2. Shear Strength Parameters:
The shear strength of the soil depends on the angle of internal friction (φ) and the cohesion (c) of the soil.
In this case, the soil is described as sand with an angle of internal friction (φ) of 32°. As sand is a cohesionless soil, the cohesion (c) is assumed to be zero.
3. Effective Strength:
The effective strength (τ') of the soil can be calculated using the Mohr-Coulomb shear strength equation:
τ' = c' + σ' * tan(φ')
For cohesionless soils, the effective strength equation simplifies to:
τ' = σ' * tan(φ')
In this case, the effective strength at a depth of 6m can be calculated as follows:
τ' = σ' * tan(φ')
= (Ysat - Yw) * tan(φ') [Since c' = 0]
Substituting the given values:
τ' = (20 kN/m^3 - 10 kN/m^3) * tan(32°)
= 10 kN/m^3 * tan(32°)
Using a calculator, we can determine:
τ' ≈ 5.91 kN/m^2
Therefore, the effective strength at a depth of 6m from the ground surface is approximately 5.91 kN/m^2.
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The soil strata consisted of sand-extending up to great depth.The water table was found to be at the ground surface. The soil parameters Ysat= 20kn/m^3 and phi=32.Find the effective strength at a depth of 6 m from the ground surface. Take Yw=10 kN/m3 ANS 49 kN/m^2 � . e 3 d "' _ 32�. Find the - 20 kN/m -an "' - � - be at the ground surface. The soil parameters_ Ysat - = 10 kN/m3] effective strength at a depth of 6 m from the ground surface?
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The soil strata consisted of sand-extending up to great depth.The water table was found to be at the ground surface. The soil parameters Ysat= 20kn/m^3 and phi=32.Find the effective strength at a depth of 6 m from the ground surface. Take Yw=10 kN/m3 ANS 49 kN/m^2 � . e 3 d "' _ 32�. Find the - 20 kN/m -an "' - � - be at the ground surface. The soil parameters_ Ysat - = 10 kN/m3] effective strength at a depth of 6 m from the ground surface? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about The soil strata consisted of sand-extending up to great depth.The water table was found to be at the ground surface. The soil parameters Ysat= 20kn/m^3 and phi=32.Find the effective strength at a depth of 6 m from the ground surface. Take Yw=10 kN/m3 ANS 49 kN/m^2 � . e 3 d "' _ 32�. Find the - 20 kN/m -an "' - � - be at the ground surface. The soil parameters_ Ysat - = 10 kN/m3] effective strength at a depth of 6 m from the ground surface? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The soil strata consisted of sand-extending up to great depth.The water table was found to be at the ground surface. The soil parameters Ysat= 20kn/m^3 and phi=32.Find the effective strength at a depth of 6 m from the ground surface. Take Yw=10 kN/m3 ANS 49 kN/m^2 � . e 3 d "' _ 32�. Find the - 20 kN/m -an "' - � - be at the ground surface. The soil parameters_ Ysat - = 10 kN/m3] effective strength at a depth of 6 m from the ground surface?.
The soil strata consisted of sand-extending up to great depth.The water table was found to be at the ground surface. The soil parameters Ysat= 20kn/m^3 and phi=32.Find the effective strength at a depth of 6 m from the ground surface. Take Yw=10 kN/m3 ANS 49 kN/m^2 � . e 3 d "' _ 32�. Find the - 20 kN/m -an "' - � - be at the ground surface. The soil parameters_ Ysat - = 10 kN/m3] effective strength at a depth of 6 m from the ground surface? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about The soil strata consisted of sand-extending up to great depth.The water table was found to be at the ground surface. The soil parameters Ysat= 20kn/m^3 and phi=32.Find the effective strength at a depth of 6 m from the ground surface. Take Yw=10 kN/m3 ANS 49 kN/m^2 � . e 3 d "' _ 32�. Find the - 20 kN/m -an "' - � - be at the ground surface. The soil parameters_ Ysat - = 10 kN/m3] effective strength at a depth of 6 m from the ground surface? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The soil strata consisted of sand-extending up to great depth.The water table was found to be at the ground surface. The soil parameters Ysat= 20kn/m^3 and phi=32.Find the effective strength at a depth of 6 m from the ground surface. Take Yw=10 kN/m3 ANS 49 kN/m^2 � . e 3 d "' _ 32�. Find the - 20 kN/m -an "' - � - be at the ground surface. The soil parameters_ Ysat - = 10 kN/m3] effective strength at a depth of 6 m from the ground surface?.
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