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3g of activated charcoal was added to 50 ml of acetic solution (0.06N) in a flask.After an hour it was filtered and the strength of the filtrate was found to be 0.042 N. The amount of acetic acid adsorbed (per gram of charcoal) is. ?
Verified Answer
3g of activated charcoal was added to 50 ml of acetic solution (0.06N)...
Answer
Amount adsorbed
= (0.060 – 0.042) x 50 x 10
–3
 x 60
= 0.018 x 50 x 60 x 10
–3
= 0.018 x 3 
= 0.054 gm
= 54 mg
Amount adsorbed per gram of activated charcoal = 54/3 = 18 mg
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3g of activated charcoal was added to 50 ml of acetic solution (0.06N) in a flask.After an hour it was filtered and the strength of the filtrate was found to be 0.042 N. The amount of acetic acid adsorbed (per gram of charcoal) is. ?
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