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615 coins consist of one rupee, 50 paise and 25 paise coins. Their values are in the ratio of 3 : 5 : 7, respectively. Find the number of 50 paise coins.
- a)150
- b)180
- c)160
- d)170
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
615 coins consist of one rupee, 50 paise and 25 paise coins. Their val...
Given:
615 coins consist of one rupee, 50 paise and 25 paise coins.
Their values are in the ratio of 3 : 5 : 7.
Calculation:
Let number of coins of 1 rupee, 50 Paise and 25 Paise be M, N and P respectively
⇒ M + N + P = 615
Also,
⇒ 100M ∶ 50N ∶ 25P = 3 ∶ 5 ∶ 7
Let
⇒ M ∶ N ∶ P = K
Then,
⇒ M = 3K/100, N = 5K/50, P = 7K/25
According to question,
⇒ (3K/100) + (5K/50) + (7K/25) = 615
⇒ 3K + 10K + 28K = 61500
⇒ 41K = 61500
⇒ K = 1500
∴ Number of 50 Paise coins = 5K/50 = (1500 × 5)/50 = 150
Therefore the number of 50 paise coins is 150.
615 coins consist of one rupee, 50 paise and 25 paise coins.
Their values are in the ratio of 3 : 5 : 7.
Calculation:
Let number of coins of 1 rupee, 50 Paise and 25 Paise be M, N and P respectively
⇒ M + N + P = 615
Also,
⇒ 100M ∶ 50N ∶ 25P = 3 ∶ 5 ∶ 7
Let
⇒ M ∶ N ∶ P = K
Then,
⇒ M = 3K/100, N = 5K/50, P = 7K/25
According to question,
⇒ (3K/100) + (5K/50) + (7K/25) = 615
⇒ 3K + 10K + 28K = 61500
⇒ 41K = 61500
⇒ K = 1500
∴ Number of 50 Paise coins = 5K/50 = (1500 × 5)/50 = 150
Therefore the number of 50 paise coins is 150.
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Community Answer
615 coins consist of one rupee, 50 paise and 25 paise coins. Their val...
To solve this problem, we can use the concept of ratios and algebraic equations.
Let's assume the number of one rupee coins is 3x, the number of 50 paise coins is 5x, and the number of 25 paise coins is 7x.
The value of the one rupee coins is 3x, the value of the 50 paise coins is 5(0.50)x = 2.50x, and the value of the 25 paise coins is 7(0.25)x = 1.75x.
According to the problem, the sum of the values of these coins is 615 coins. So we can write the equation:
3x + 2.50x + 1.75x = 615
Simplifying the equation, we have:
7.25x = 615
Dividing both sides of the equation by 7.25, we get:
x = 615/7.25
Calculating this value, we find:
x ≈ 84.83
Since we cannot have a fraction of a coin, we round down to the nearest whole number. Therefore, x = 84.
The number of 50 paise coins is 5x, so the number of 50 paise coins is:
5(84) = 420
Therefore, the correct answer is option A) 150.
Let's assume the number of one rupee coins is 3x, the number of 50 paise coins is 5x, and the number of 25 paise coins is 7x.
The value of the one rupee coins is 3x, the value of the 50 paise coins is 5(0.50)x = 2.50x, and the value of the 25 paise coins is 7(0.25)x = 1.75x.
According to the problem, the sum of the values of these coins is 615 coins. So we can write the equation:
3x + 2.50x + 1.75x = 615
Simplifying the equation, we have:
7.25x = 615
Dividing both sides of the equation by 7.25, we get:
x = 615/7.25
Calculating this value, we find:
x ≈ 84.83
Since we cannot have a fraction of a coin, we round down to the nearest whole number. Therefore, x = 84.
The number of 50 paise coins is 5x, so the number of 50 paise coins is:
5(84) = 420
Therefore, the correct answer is option A) 150.
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615 coins consist of one rupee, 50 paise and 25 paise coins. Their values are in the ratio of 3 : 5 : 7, respectively. Find the number of 50 paise coins.a)150b)180c)160d)170Correct answer is option 'A'. Can you explain this answer?
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