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Let x be the rational number equidistant from -2/3 and 3/5 on the number line. Let y be the rational number equidistant from-1 and 4/5 on the number line. Find x and y . Hence evaluate (x y) ÷(x-y).?
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Let x be the rational number equidistant from -2/3 and 3/5 on the numb...
Let's solve the problem step by step:
Finding x:
To find the rational number equidistant from -2/3 and 3/5, we need to find the average (mean) of these two numbers. The average of two numbers can be found by adding them and dividing by 2.
-2/3 + 3/5 = (-10/15) + (9/15) = -1/15
Since -1/15 is the average of -2/3 and 3/5, it is the rational number equidistant from them. Therefore, x = -1/15.
Finding y:
To find the rational number equidistant from -1 and 4/5, we also need to find the average of these two numbers.
-1 + 4/5 = (-5/5) + (4/5) = -1/5
So, the rational number equidistant from -1 and 4/5 is -1/5. Therefore, y = -1/5.
Evaluating (x y) ÷ (x-y):
To evaluate this expression, we substitute the values of x and y that we found:
(x y) ÷ (x-y) = (-1/15) ÷ (-1/15 - (-1/5))
To divide fractions, we invert and multiply the second fraction. So, we have:
(-1/15) ÷ (-1/15 - (-1/5)) = (-1/15) ÷ (-1/15 + 1/5)
Next, we find a common denominator for the two fractions:
(-1/15) ÷ (-1/15 + 1/5) = (-1/15) ÷ (-1/15 + 3/15)
Combining the fractions:
(-1/15) ÷ (2/15) = (-1/15) * (15/2)
Canceling out common factors:
(-1/15) * (15/2) = -1/2
Therefore, (x y) ÷ (x-y) = -1/2.
In summary:
x = -1/15
y = -1/5
(x y) ÷ (x-y) = -1/2
Finding x:
To find the rational number equidistant from -2/3 and 3/5, we need to find the average (mean) of these two numbers. The average of two numbers can be found by adding them and dividing by 2.
-2/3 + 3/5 = (-10/15) + (9/15) = -1/15
Since -1/15 is the average of -2/3 and 3/5, it is the rational number equidistant from them. Therefore, x = -1/15.
Finding y:
To find the rational number equidistant from -1 and 4/5, we also need to find the average of these two numbers.
-1 + 4/5 = (-5/5) + (4/5) = -1/5
So, the rational number equidistant from -1 and 4/5 is -1/5. Therefore, y = -1/5.
Evaluating (x y) ÷ (x-y):
To evaluate this expression, we substitute the values of x and y that we found:
(x y) ÷ (x-y) = (-1/15) ÷ (-1/15 - (-1/5))
To divide fractions, we invert and multiply the second fraction. So, we have:
(-1/15) ÷ (-1/15 - (-1/5)) = (-1/15) ÷ (-1/15 + 1/5)
Next, we find a common denominator for the two fractions:
(-1/15) ÷ (-1/15 + 1/5) = (-1/15) ÷ (-1/15 + 3/15)
Combining the fractions:
(-1/15) ÷ (2/15) = (-1/15) * (15/2)
Canceling out common factors:
(-1/15) * (15/2) = -1/2
Therefore, (x y) ÷ (x-y) = -1/2.
In summary:
x = -1/15
y = -1/5
(x y) ÷ (x-y) = -1/2
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Let x be the rational number equidistant from -2/3 and 3/5 on the number line. Let y be the rational number equidistant from-1 and 4/5 on the number line. Find x and y . Hence evaluate (x y) ÷(x-y).?
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Let x be the rational number equidistant from -2/3 and 3/5 on the number line. Let y be the rational number equidistant from-1 and 4/5 on the number line. Find x and y . Hence evaluate (x y) ÷(x-y).? for Class 7 2024 is part of Class 7 preparation. The Question and answers have been prepared according to the Class 7 exam syllabus. Information about Let x be the rational number equidistant from -2/3 and 3/5 on the number line. Let y be the rational number equidistant from-1 and 4/5 on the number line. Find x and y . Hence evaluate (x y) ÷(x-y).? covers all topics & solutions for Class 7 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let x be the rational number equidistant from -2/3 and 3/5 on the number line. Let y be the rational number equidistant from-1 and 4/5 on the number line. Find x and y . Hence evaluate (x y) ÷(x-y).?.
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