If a,b,c belong to N and 2a b c=12 then the maximum value of a^3bc^2 i...
Given Information:
a, b, and c belong to the set of natural numbers (N).
2a + b + c = 12
Objective:
To find the maximum value of a^3bc^2.
Solution:
Let's start by rearranging the given equation:
2a = 12 - b - c
Step 1: Determine the Range of Values for a
In order to maximize the value of a^3bc^2, we need to determine the range of values for a.
The smallest value of a occurs when b and c are at their maximum possible values, which is 6 (since a, b, and c are natural numbers and their sum is 12). In this case, 2a = 12 - 6 - 6 = 0, so a = 0.
The largest value of a occurs when b and c are at their minimum values, which is 1. In this case, 2a = 12 - 1 - 1 = 10, so a = 5.
Therefore, the range of values for a is 0 ≤ a ≤ 5.
Step 2: Determine the Range of Values for b and c
Since a, b, and c are natural numbers, the range of values for b and c is 1 ≤ b, c ≤ 6.
Step 3: Evaluating a^3bc^2
Let's evaluate a^3bc^2 for each possible combination of values for a, b, and c within the given ranges:
a = 0, b = 6, c = 6: (0)^3 * 6 * (6)^2 = 0
a = 5, b = 1, c = 1: (5)^3 * 1 * (1)^2 = 125
For all other combinations of values, a is less than 5, so a^3bc^2 will be less than 125.
Step 4: Determining the Maximum Value
From the above evaluations, we can see that the maximum value of a^3bc^2 is 125, which occurs when a = 5, b = 1, and c = 1.
Answer:
The maximum value of a^3bc^2 is 125 when a = 5, b = 1, and c = 1.