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A particle of charge q1=+6.0μc is located on the x-axis at the point x1=5.1cm. A second particle of charge q2=-5.0μc is placed on the x- axis at x2=3.4cm. What is the absolute electric potential at the origin (x=0)?How much work must be perform in order to slowly move a charge of q3=-7.0μc from infinity to the origin,whilst keeping the other two charges fixed ?
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A particle of charge q1=+6.0μc is located on the x-axis at the point x...
Electric Potential at the Origin:
- Calculate the electric potential due to each charge at the origin using the formula V=kq/r, where k is the electrostatic constant.
- Electric potential due to q1: V1=k*q1/(5.1*10^-2)=9*10^9*6*10^-6/5.1*10^-2 V
- Electric potential due to q2: V2=k*q2/(3.4*10^-2)=-9*10^9*5*10^-6/3.4*10^-2 V
- Total electric potential at the origin: V=V1+V2

Work Done to Move q3 to the Origin:
- The work done to move a charge q3 from infinity to a point is given by W=q3*V3, where V3 is the electric potential at that point.
- Calculate the total electric potential at the origin, V3, due to q1, q2, and q3.
- V3=V1+V2+k*q3/r, where r is the distance of q3 from the origin.
- Substitute the values of V1, V2, q3, and r into the above equation to find V3.
- Finally, calculate the work done by multiplying q3 and V3.
By following these steps, you can determine the absolute electric potential at the origin and the work required to move a charge from infinity to the origin while keeping the other charges fixed.
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A particle of charge q1=+6.0μc is located on the x-axis at the point x...
V1= keq1/X1 = 8.988×10^9×6×10^-6/5.1×10^-2 = 1.06×10^6VV2=keq2/X2 =8.988×10^9×-5×10^-6/3.4×10^-2 = -1.32×10^6VV1+ V2= -2.64×10^5W=q3V =(-7×10^-6)(-2.64×10^5) =1.85J
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A particle of charge q1=+6.0μc is located on the x-axis at the point x1=5.1cm. A second particle of charge q2=-5.0μc is placed on the x- axis at x2=3.4cm. What is the absolute electric potential at the origin (x=0)?How much work must be perform in order to slowly move a charge of q3=-7.0μc from infinity to the origin,whilst keeping the other two charges fixed ?
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A particle of charge q1=+6.0μc is located on the x-axis at the point x1=5.1cm. A second particle of charge q2=-5.0μc is placed on the x- axis at x2=3.4cm. What is the absolute electric potential at the origin (x=0)?How much work must be perform in order to slowly move a charge of q3=-7.0μc from infinity to the origin,whilst keeping the other two charges fixed ? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A particle of charge q1=+6.0μc is located on the x-axis at the point x1=5.1cm. A second particle of charge q2=-5.0μc is placed on the x- axis at x2=3.4cm. What is the absolute electric potential at the origin (x=0)?How much work must be perform in order to slowly move a charge of q3=-7.0μc from infinity to the origin,whilst keeping the other two charges fixed ? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle of charge q1=+6.0μc is located on the x-axis at the point x1=5.1cm. A second particle of charge q2=-5.0μc is placed on the x- axis at x2=3.4cm. What is the absolute electric potential at the origin (x=0)?How much work must be perform in order to slowly move a charge of q3=-7.0μc from infinity to the origin,whilst keeping the other two charges fixed ?.
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