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A current is passed through a Ga(NO3)3 for 1.5 hours, and after this time period the mass of metal produced was 6.3 grams. What is the current, in amperes, that is required to produce such an amount of gallium?
- a)1.7 A
- b)5.0 A
- c)100 A
- d)300 A
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A current is passed through a Ga(NO3)3 for 1.5 hours, and after this t...
To determine the current required to produce 6.3 grams of gallium (Ga) in 1.5 hours, we can use Faraday's law of electrolysis.
The key formula for Faraday's law is:
M = (Q * Molar mass) / (n * F)
Where:
M is the mass of the substance produced (in grams)
Q is the total charge passed through the electrolyte (in Coulombs)
Molar mass is the molar mass of the substance (in grams per mole)
n is the number of moles of electrons required for the reaction
F is Faraday's constant (96,485 Coulombs per mole of electrons)
In this case, we are given that the mass produced is 6.3 grams and the time is 1.5 hours. We need to find the current (I) in amperes.
1. Calculate the total charge passed through the electrolyte.
We know that current (I) is equal to charge (Q) divided by time (t). Therefore, we can rearrange the formula to find the charge:
Q = I * t
Q = I * 1.5
2. Calculate the number of moles of gallium produced.
We can use the molar mass of gallium to convert the mass produced to moles:
n = M / Molar mass
n = 6.3 / (69.723 g/mol)
3. Calculate the current (I) using Faraday's law.
Substitute the values into the formula and solve for I:
M = (Q * Molar mass) / (n * F)
6.3 = (I * 1.5 * 69.723) / (n * 96,485)
I = (6.3 * n * 96,485) / (1.5 * 69.723)
4. Calculate the current in amperes.
Substitute the value of n and solve for I:
I = (6.3 * 0.0902 * 96,485) / (1.5 * 69.723)
I ≈ 5.0 A
Therefore, the current required to produce 6.3 grams of gallium in 1.5 hours is approximately 5.0 Amperes (A), which corresponds to option (B).
The key formula for Faraday's law is:
M = (Q * Molar mass) / (n * F)
Where:
M is the mass of the substance produced (in grams)
Q is the total charge passed through the electrolyte (in Coulombs)
Molar mass is the molar mass of the substance (in grams per mole)
n is the number of moles of electrons required for the reaction
F is Faraday's constant (96,485 Coulombs per mole of electrons)
In this case, we are given that the mass produced is 6.3 grams and the time is 1.5 hours. We need to find the current (I) in amperes.
1. Calculate the total charge passed through the electrolyte.
We know that current (I) is equal to charge (Q) divided by time (t). Therefore, we can rearrange the formula to find the charge:
Q = I * t
Q = I * 1.5
2. Calculate the number of moles of gallium produced.
We can use the molar mass of gallium to convert the mass produced to moles:
n = M / Molar mass
n = 6.3 / (69.723 g/mol)
3. Calculate the current (I) using Faraday's law.
Substitute the values into the formula and solve for I:
M = (Q * Molar mass) / (n * F)
6.3 = (I * 1.5 * 69.723) / (n * 96,485)
I = (6.3 * n * 96,485) / (1.5 * 69.723)
4. Calculate the current in amperes.
Substitute the value of n and solve for I:
I = (6.3 * 0.0902 * 96,485) / (1.5 * 69.723)
I ≈ 5.0 A
Therefore, the current required to produce 6.3 grams of gallium in 1.5 hours is approximately 5.0 Amperes (A), which corresponds to option (B).
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Community Answer
A current is passed through a Ga(NO3)3 for 1.5 hours, and after this t...
Faraday’s Law of electrolysis gives us the following formula:
It = nF
where n is the moles of electrons and F is Faraday’s constant. Use 100,000 or 10⁵ Coulomb/mole of electrons for any calculation.
We are trying to solve for current with known values for time t = 1.5 hours, mass m = 6.3 grams, molar mass M = 69.7 or 70.0 grams/mole, and valency number of the ions z = 3. Plug into the equation:
Grab three zeros and add it to 6.3 grams to make 6300 grams, which cancels out 90 and 70 in the denominator. We are left with 3 and 100 in the numerator and 60 in the denominator. So the correct answer is 5.0 Amperes.
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A current is passed through a Ga(NO3)3 for 1.5 hours, and after this time period the mass of metal produced was 6.3 grams. What is the current, in amperes, that is required to produce such an amount of gallium?a)1.7 Ab)5.0 Ac)100 Ad)300 ACorrect answer is option 'B'. Can you explain this answer? for MCAT 2025 is part of MCAT preparation. The Question and answers have been prepared according to the MCAT exam syllabus. Information about A current is passed through a Ga(NO3)3 for 1.5 hours, and after this time period the mass of metal produced was 6.3 grams. What is the current, in amperes, that is required to produce such an amount of gallium?a)1.7 Ab)5.0 Ac)100 Ad)300 ACorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for MCAT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A current is passed through a Ga(NO3)3 for 1.5 hours, and after this time period the mass of metal produced was 6.3 grams. What is the current, in amperes, that is required to produce such an amount of gallium?a)1.7 Ab)5.0 Ac)100 Ad)300 ACorrect answer is option 'B'. Can you explain this answer?.
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