Airforce X Y / Indian Navy SSR Exam > Airforce X Y / Indian Navy SSR Questions > A dishonest shopkeeper pretends to sell his g...
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A dishonest shopkeeper pretends to sell his goods at cost price but uses false weights and gain 10%. How much false weight he is using instead 1 kg weight?
- a)909.09 gm
- b)900 gm
- c)920.30 gm
- d)911.12 gm
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A dishonest shopkeeper pretends to sell his goods at cost price but us...
Given:
Shopkeeper's percentage gain = 10%
Concept:
The principle of false weight in dishonest dealings follows this rule: ( False Weight / True Weight) = (100 / (100 + Gain%))
Calculations:
⇒ False Weight = True Weight × 100/(100 + Gain%)
⇒ False Weight = 1 × 100/(100 + 10)
⇒ False Weight = 0.909 kg (approximately)
Therefore, instead of 1 kg, the shopkeeper is using approximately 0.909 kg.
Shopkeeper's percentage gain = 10%
Concept:
The principle of false weight in dishonest dealings follows this rule: ( False Weight / True Weight) = (100 / (100 + Gain%))
Calculations:
⇒ False Weight = True Weight × 100/(100 + Gain%)
⇒ False Weight = 1 × 100/(100 + 10)
⇒ False Weight = 0.909 kg (approximately)
Therefore, instead of 1 kg, the shopkeeper is using approximately 0.909 kg.
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Community Answer
A dishonest shopkeeper pretends to sell his goods at cost price but us...
Dishonest shopkeeper's trick:
The dishonest shopkeeper is pretending to sell his goods at cost price but is using false weights. This means that he is giving less weight than what the customer is actually paying for.
Calculating the false weight:
Let's assume that the shopkeeper is using 'x' grams of false weight instead of 1 kg weight.
Calculating the actual weight received by the customer:
Since the shopkeeper is using false weights, the customer is actually receiving less weight than what they think they are getting. Let's calculate the actual weight received by the customer.
1 kg = 1000 grams
Weight received by the customer = 1000 - x grams
Calculating the cost price:
The dishonest shopkeeper is pretending to sell his goods at cost price. This means that he is not adding any profit to the cost price.
Calculating the selling price:
The shopkeeper is gaining 10% profit on the cost price. So, the selling price is 110% of the cost price.
Selling price = 110% of cost price
Setting up the equation:
Since the shopkeeper is pretending to sell at cost price, the selling price should be equal to the actual cost price.
110% of cost price = Weight received by the customer
110% of cost price = 1000 - x
Solving the equation:
To find the value of 'x', we need to solve the equation.
110% of cost price = 1000 - x
110/100 * cost price = 1000 - x
1.1 * cost price = 1000 - x
cost price = (1000 - x) / 1.1
Calculating the value of 'x':
Since the cost price is the actual selling price, we can substitute the value of cost price in the equation and solve for 'x'.
cost price = (1000 - x) / 1.1
cost price = 1000 - x
x = 1000 - cost price
Given that the shopkeeper is gaining 10% profit:
Since the shopkeeper is gaining 10% profit, the cost price is 90% of the selling price.
cost price = 90% of selling price
cost price = 90/100 * selling price
cost price = 0.9 * selling price
Substituting the value of the cost price:
We can substitute the value of the cost price in the equation and solve for 'x'.
0.9 * selling price = 1000 - x
selling price = (1000 - x) / 0.9
Comparing the two equations:
We have two equations for the selling price:
selling price = 110% of cost price
selling price = (1000 - x) / 0.9
Since both equations represent the selling price, we can equate them and solve for 'x'.
110% of cost price = (1000 - x) / 0.9
1.1 * cost price = (1000 - x) / 0.9
Solving the equation:
To find the value of 'x', we need to solve the equation.
The dishonest shopkeeper is pretending to sell his goods at cost price but is using false weights. This means that he is giving less weight than what the customer is actually paying for.
Calculating the false weight:
Let's assume that the shopkeeper is using 'x' grams of false weight instead of 1 kg weight.
Calculating the actual weight received by the customer:
Since the shopkeeper is using false weights, the customer is actually receiving less weight than what they think they are getting. Let's calculate the actual weight received by the customer.
1 kg = 1000 grams
Weight received by the customer = 1000 - x grams
Calculating the cost price:
The dishonest shopkeeper is pretending to sell his goods at cost price. This means that he is not adding any profit to the cost price.
Calculating the selling price:
The shopkeeper is gaining 10% profit on the cost price. So, the selling price is 110% of the cost price.
Selling price = 110% of cost price
Setting up the equation:
Since the shopkeeper is pretending to sell at cost price, the selling price should be equal to the actual cost price.
110% of cost price = Weight received by the customer
110% of cost price = 1000 - x
Solving the equation:
To find the value of 'x', we need to solve the equation.
110% of cost price = 1000 - x
110/100 * cost price = 1000 - x
1.1 * cost price = 1000 - x
cost price = (1000 - x) / 1.1
Calculating the value of 'x':
Since the cost price is the actual selling price, we can substitute the value of cost price in the equation and solve for 'x'.
cost price = (1000 - x) / 1.1
cost price = 1000 - x
x = 1000 - cost price
Given that the shopkeeper is gaining 10% profit:
Since the shopkeeper is gaining 10% profit, the cost price is 90% of the selling price.
cost price = 90% of selling price
cost price = 90/100 * selling price
cost price = 0.9 * selling price
Substituting the value of the cost price:
We can substitute the value of the cost price in the equation and solve for 'x'.
0.9 * selling price = 1000 - x
selling price = (1000 - x) / 0.9
Comparing the two equations:
We have two equations for the selling price:
selling price = 110% of cost price
selling price = (1000 - x) / 0.9
Since both equations represent the selling price, we can equate them and solve for 'x'.
110% of cost price = (1000 - x) / 0.9
1.1 * cost price = (1000 - x) / 0.9
Solving the equation:
To find the value of 'x', we need to solve the equation.
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A dishonest shopkeeper pretends to sell his goods at cost price but uses false weights and gain 10%. How much false weight he is using instead 1 kg weight? a)909.09 gmb)900 gmc)920.30 gmd)911.12 gmCorrect answer is option 'A'. Can you explain this answer?
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A dishonest shopkeeper pretends to sell his goods at cost price but uses false weights and gain 10%. How much false weight he is using instead 1 kg weight? a)909.09 gmb)900 gmc)920.30 gmd)911.12 gmCorrect answer is option 'A'. Can you explain this answer? for Airforce X Y / Indian Navy SSR 2025 is part of Airforce X Y / Indian Navy SSR preparation. The Question and answers have been prepared according to the Airforce X Y / Indian Navy SSR exam syllabus. Information about A dishonest shopkeeper pretends to sell his goods at cost price but uses false weights and gain 10%. How much false weight he is using instead 1 kg weight? a)909.09 gmb)900 gmc)920.30 gmd)911.12 gmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Airforce X Y / Indian Navy SSR 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A dishonest shopkeeper pretends to sell his goods at cost price but uses false weights and gain 10%. How much false weight he is using instead 1 kg weight? a)909.09 gmb)900 gmc)920.30 gmd)911.12 gmCorrect answer is option 'A'. Can you explain this answer?.
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