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The hypotenuse of right triangle ABC shown below is 16 inches long. The sine of angle A is 3/5. About how many inches long is BC?
  • a)
    8.0
  • b)
    9.6
  • c)
    12.4
  • d)
    14.3
  • e)
    15.6
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The hypotenuse of right triangle ABC shown below is 16 inches long. Th...
One way to solve this problem is to use SOH CAH TOA for angle A. You are given that the sine of angle A is 3/5, which means that the ratio of the length of the side opposite angle A to the length of the hypotenuse is 3 to 5.
So, the ratio 3/5 is equal to the ratio BC /AC. You are given that AC, the hypotenuse, is equal to 16, so now you can set up a proportion, cross-multiply, and solve for BC, as follows:
3/5 = BC/AC
5BC = 3AC
5BC = 3(16)
5BC = 48
BC = 9.6
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The hypotenuse of right triangle ABC shown below is 16 inches long. The sine of angle A is 3/5. About how many inches long is BC?a)8.0b)9.6c)12.4d)14.3e)15.6Correct answer is option 'B'. Can you explain this answer?
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