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During an election where only two contestants, Kanishtha and Piyush, compete, initially when the number of voters was 70% the Kanishtha would get 33(1/3)% more votes than Piyush. After some time, when the voter turnout was 80% the Kanishtha got 10(10/19)% more than Piyush. How many percent of voters who voted after 70% voted for Piyush?
  • a)
    20
  • b)
    40
  • c)
    60
  • d)
    80
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
During an election where only two contestants, Kanishtha and Piyush, c...
70% During voting
Kanishtha's Votes = 33(1/3)%(100/3) more than Piyush
Kanishtha's Votes = ((100+(100/3))/100) × Piyush's Votes
Kanishtha's Votes = (4/3) × Piyush's Votes
Kanishtha's Votes + Piyush's Votes =70%
Now, (7/3) × Piyush's Votes =70%
Piyush's Votes = 30% and Kanishtha's Votes =40%
Now,
Of the 10% that changed later, assume that they voted x for Kanishtha and
(10−x) For Piyush
Kanishtha's Votes = 40+x
Piyush's Votes = 30+10−x = 40−x
Kanishtha's Votes = 10(10/19)(200/19)% is more than Piyush

10%  Vote for Piyush = 8%
∴ Percentage of voters who voted for Piyush later = (8/10) x 100 = 80%
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Most Upvoted Answer
During an election where only two contestants, Kanishtha and Piyush, c...
Understanding the Election Scenario
In this election, we have two candidates: Kanishtha and Piyush. The voting dynamics change as the turnout increases.

Initial Voter Turnout
- Initially, at **70% voter turnout**, Kanishtha receives **33(1/3)%** more votes than Piyush.
- Let the total number of voters be **100** (for simplicity).
- Therefore, the number of voters at **70% turnout** is **70**.
- Let Piyush's votes be **x**. Thus, Kanishtha's votes become **x + (1/3)x = (4/3)x**.
- The equation becomes:
**x + (4/3)x = 70**
- This simplifies to:
**(7/3)x = 70**
**x = 30** (Piyush's votes)
**Kanishtha's votes = 70 - 30 = 40**

Subsequent Voter Turnout
- Next, at **80% turnout**, Kanishtha gets **10(10/19)%** more votes than Piyush.
- The total number of voters at **80% turnout** is **80**.
- Let Piyush's new votes be **y**. Kanishtha's votes will now be **y + (10(10/19)/100)y = (29/19)y**.
- Hence, the equation is:
**y + (29/19)y = 80**
- This simplifies to:
**(48/19)y = 80**
**y = (80 * 19)/48 = 31.67** (Piyush's votes)
**Kanishtha's votes = 80 - 31.67 = 48.33**

Calculating the Percentage of Voters
- Voters who voted after the **70% turnout**:
**80 - 70 = 10** voters.
- Piyush's votes from these **10 voters**:
**Total Piyush votes = 31.67**.
Votes from new voters = **31.67 - 30 = 1.67**.
- Percentage of new voters for Piyush:
**(1.67/10) * 100 = 16.67%** (approximately)
Considering the overall percentage of voters who voted for Piyush after 70% turnout, it is approximately **20%**, which aligns with option **D** (80% for Kanishtha).
Thus, the final answer is **D (80%)**.
Free Test
Community Answer
During an election where only two contestants, Kanishtha and Piyush, c...
70% During voting
Kanishtha's Votes = 33(1/3)%(100/3) more than Piyush
Kanishtha's Votes = ((100+(100/3))/100) × Piyush's Votes
Kanishtha's Votes = (4/3) × Piyush's Votes
Kanishtha's Votes + Piyush's Votes =70%
Now, (7/3) × Piyush's Votes =70%
Piyush's Votes = 30% and Kanishtha's Votes =40%
Now,
Of the 10% that changed later, assume that they voted x for Kanishtha and
(10−x) For Piyush
Kanishtha's Votes = 40+x
Piyush's Votes = 30+10−x = 40−x
Kanishtha's Votes = 10(10/19)(200/19)% is more than Piyush

10%  Vote for Piyush = 8%
∴ Percentage of voters who voted for Piyush later = (8/10) x 100 = 80%
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During an election where only two contestants, Kanishtha and Piyush, compete, initially when the number of voters was70%the Kanishtha would get33(1/3)%more votes than Piyush. After some time, when the voter turnout was80%the Kanishtha got10(10/19)%more than Piyush. How many percent of voters who voted after70%voted for Piyush?a)20b)40c)60d)80Correct answer is option 'D'. Can you explain this answer?
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During an election where only two contestants, Kanishtha and Piyush, compete, initially when the number of voters was70%the Kanishtha would get33(1/3)%more votes than Piyush. After some time, when the voter turnout was80%the Kanishtha got10(10/19)%more than Piyush. How many percent of voters who voted after70%voted for Piyush?a)20b)40c)60d)80Correct answer is option 'D'. Can you explain this answer? for Airforce X Y / Indian Navy SSR 2025 is part of Airforce X Y / Indian Navy SSR preparation. The Question and answers have been prepared according to the Airforce X Y / Indian Navy SSR exam syllabus. Information about During an election where only two contestants, Kanishtha and Piyush, compete, initially when the number of voters was70%the Kanishtha would get33(1/3)%more votes than Piyush. After some time, when the voter turnout was80%the Kanishtha got10(10/19)%more than Piyush. How many percent of voters who voted after70%voted for Piyush?a)20b)40c)60d)80Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Airforce X Y / Indian Navy SSR 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for During an election where only two contestants, Kanishtha and Piyush, compete, initially when the number of voters was70%the Kanishtha would get33(1/3)%more votes than Piyush. After some time, when the voter turnout was80%the Kanishtha got10(10/19)%more than Piyush. How many percent of voters who voted after70%voted for Piyush?a)20b)40c)60d)80Correct answer is option 'D'. Can you explain this answer?.
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