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If a fixed amount of power is to be transmitted over a certain length with fixed power loss, it can be said that volume of conductor is
  • a)
    inversely proportional to magnitude of the voltage and power factor of the load.
  • b)
    inversely proportional to square of the voltage and square of power factor of theload.
  • c)
    proportional to square of voltage and power factor of the load.
  • d)
    proportional to magnitude of the voltageonly.
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If a fixed amount of power is to be transmitted over a certain length ...
Explanation:

To understand why the volume of the conductor is inversely proportional to the square of the voltage and the square of the power factor of the load, we need to consider the power equation and the relationship between power, voltage, current, and resistance.

Power Equation:
The power (P) transmitted through a conductor can be calculated using the following equation:

P = VI cos(θ)

Where:
- P is the power transmitted in watts (W)
- V is the voltage across the conductor in volts (V)
- I is the current flowing through the conductor in amperes (A)
- cos(θ) is the power factor of the load

Relationship between Power, Voltage, Current, and Resistance:
Using Ohm's Law, we know that the current flowing through a conductor is directly proportional to the voltage and inversely proportional to the resistance:

I = V/R

Where:
- R is the resistance of the conductor in ohms (Ω)

Volume of Conductor:
Now, let's consider the volume of the conductor. The volume of a conductor is directly proportional to its cross-sectional area (A) and length (L):

Volume = A * L

Inverse Proportion:
From the power equation, we can rewrite it as:

P = (V^2/R) cos(θ)

We can see that the power (P) is inversely proportional to the resistance (R). Since the power loss in the conductor is fixed, we can conclude that the resistance (R) is fixed.

From Ohm's Law, we know that the current (I) is directly proportional to the voltage (V) and inversely proportional to the resistance (R). Therefore, the current (I) is also fixed.

We can rewrite the equation for power (P) as:

P = (I^2 * R) cos(θ)

Since the power (P) and the resistance (R) are fixed, we can conclude that (I^2 * cos(θ)) is also fixed.

Conclusion:
Now, let's consider the volume equation:

Volume = A * L

From the above analysis, we know that (I^2 * cos(θ)) is fixed. We also know that the current (I) is directly proportional to the cross-sectional area (A) of the conductor.

Therefore, if the power loss is fixed, the volume of the conductor (A * L) is inversely proportional to the square of the voltage (V^2) and the square of the power factor (cos^2(θ)) of the load.

Answer:
Hence, the correct answer is option 'B': the volume of the conductor is inversely proportional to the square of the voltage and the square of the power factor of the load.
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it depends on the length of the conductor the capacitance of the line is proportional to the length of the transmission line their effect is negligible on the performance of short having a length less than 80 km and low voltage transmission accidents of the transmission line along with the conductances forms the shunted mittens the conductance and the transmission line is because of the leakage over the surface of the conductor considered a line consisting of two conductors and be each of radius are the distance between the conductors being Des shown in the diagram below minus the potential difference between the conductors and via's work QA charge on conductor QB charge on conductor vvab pencil difference between conductor and the Epsilon minus absolute primitivity QA plus QV = 0 so that QA equals QB - equals DBA equals data equals DB equals our substituting these values and voltage equation we get the capacitance between the conductors is cab is referred to as lying to line capacitance if the two conductors are in VR oppositely charge then the potential difference between them is zero then the potential of each conductor is given by one half bath the capacitance between each conductor and point of zero potential and is capacitive CN is called the capacitance to neut or capacitance to ground capacitance cab is the combination of two equal capacity and VN series thus capacitance to neutral is twice the capacitance between the conductors IE CN equals to Cave the absolute primitivity Epsilon is given by Epsilon equals epsilono Epsilon are where epsilano is the permittivity of the free space and Epsilon or is the relative primitivity of the medium prayer capacitance reactants between one conductor and neutral capacitance of the symmetrical three phase line let a balanced system of voltage be applied to a symmetrical three-phase line shown below the phasor diagram of the three phase line with equilateral spacing is shown below take the voltage of conductor to neutral as a reference phaser the potential difference between conductor and we can be written the similarly potential difference between conductors and sea is on adding equations one and two we get also combining equation three and four from equation 6 and 7 the line to neutral capacitance the capacitance of symmetrical three phase line is same as that of the two wire line Related: Capacitance of Transmission Lines?

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If a fixed amount of power is to be transmitted over a certain length with fixed power loss, it can be said that volume of conductor isa)inversely proportional to magnitude of the voltage and power factor of the load.b)inversely proportional to square of the voltage and square of power factor of theload.c)proportional to square of voltage and power factor of the load.d)proportional to magnitude of the voltageonly.Correct answer is option 'B'. Can you explain this answer?
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