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In ΔABC, AB=AC,angle A=5x+20 degree and angle B=2/5th of angle A. Find the measure of angle A,figure is in my profile pic.?
Most Upvoted Answer
In ΔABC, AB=AC,angle A=5x+20 degree and angle B=2/5th of angle A. Find...
Solution:


Given:

ΔABC, AB=AC,angle A=5x 20 degree and angle B=2/5th of angle A.


To Find:

Measure of angle A.


Explanation:

Let's assume that, angle A is x.

As per the question, AB=AC, so angle B=angle C.

Therefore, angle B=angle C=x/2.

Also, angle B=2/5th of angle A.

So, angle B=2/5x.

As we know, sum of all angles of triangle = 180 degree.

So, x + x/2 + 2/5x = 180

LCM of 2 and 5 is 10, so by solving this equation we get:

10x/10 + 5x/10 + 4x/10 = 180

19x/10 = 180

x = (10*180)/19

x = 94.736 degrees


Answer:

Therefore, the measure of angle A is 94.736 degrees.
Community Answer
In ΔABC, AB=AC,angle A=5x+20 degree and angle B=2/5th of angle A. Find...
Remember that angles opposite to equal sides r also equal so here angle b is equal to c and given that angle A is 5x+20 and b is 2/5 of a so b=c= 2/5 of 5x+20 i.e...10x+40/5 we know sum of all angles in a triangle is 180 so 5x+20+10x+40/5+10x+40/5=180then x=16
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