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Two mutually perpendicular chords AB and CD meet at a point P inside the circle such that AP = 6 cms, PB = 4 units and DP = 3 units. What is the area of the circle?
  • a)
    125π/4 sq cms
  • b)
    100π/7 sq cms
  • c)
    125π/8 sq cms
  • d)
    52π/3 sq cms
  • e)
    None of these
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Two mutually perpendicular chords AB and CD meet at a point P inside t...
As AB and CD are two chords that intersect at O, AP x PB = CP x PD
6 x 4 = CP x 3
CP = 8
From center O draw OM ⊥r AB and ON ⊥r CD.
From the center a line ⊥r to a chord bisects the chord.
So, we have AM = MB = 5 cm
MP = 1 cm, ON = 1 cm, CD = 11 cm, CN = 5.5 cm
ON2 + CN2 = OC2
12 + 5.52 + r2
1 + 30.25 = r2
Area = πr2
π x 31.25
31.25π = 125π/4 sq cms
The question is "What is the area of the circle?"
Hence, the answer is 125π/4 sq cms.
Choice A is the correct answer.
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Most Upvoted Answer
Two mutually perpendicular chords AB and CD meet at a point P inside t...
As AB and CD are two chords that intersect at O, AP x PB = CP x PD
6 x 4 = CP x 3
CP = 8
From center O draw OM ⊥r AB and ON ⊥r CD.
From the center a line ⊥r to a chord bisects the chord.
So, we have AM = MB = 5 cm
MP = 1 cm, ON = 1 cm, CD = 11 cm, CN = 5.5 cm
ON2 + CN2 = OC2
12 + 5.52 + r2
1 + 30.25 = r2
Area = πr2
π x 31.25
31.25π = 125π/4 sq cms
The question is "What is the area of the circle?"
Hence, the answer is 125π/4 sq cms.
Choice A is the correct answer.
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Community Answer
Two mutually perpendicular chords AB and CD meet at a point P inside t...
As AB and CD are two chords that intersect at O, AP x PB = CP x PD
6 x 4 = CP x 3
CP = 8
From center O draw OM ⊥r AB and ON ⊥r CD.
From the center a line ⊥r to a chord bisects the chord.
So, we have AM = MB = 5 cm
MP = 1 cm, ON = 1 cm, CD = 11 cm, CN = 5.5 cm
ON2 + CN2 = OC2
12 + 5.52 + r2
1 + 30.25 = r2
Area = πr2
π x 31.25
31.25π = 125π/4 sq cms
The question is "What is the area of the circle?"
Hence, the answer is 125π/4 sq cms.
Choice A is the correct answer.
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