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AB is a diameter of a circle with center O. A tangent is drawn at point A. C is a point on the circle such that BC produced meets the tangent at P. If ∠APC = 62º, then find the measure of the minor arc AC(i.e.∠ ABC).
  • a)
    31º
  • b)
    62º
  • c)
    28º
  • d)
    66º
  • e)
    None of these
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
AB is a diameter of a circle with center O. A tangent is drawn at poin...
Minor arc AC will create angle CBA
∠APC = 62º = ∠APB
∠BAP = 90° (diameter perpendicular to tangent)
In Δ APB,
∠APB + ∠BAP + ∠PBA = 180° 
⇒ ∠PBA = 180° - (90° + 62°)
⇒ ∠PBA = 28° 
∴ The measure of minor arc AC is 28° 
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Most Upvoted Answer
AB is a diameter of a circle with center O. A tangent is drawn at poin...
Minor arc AC will create angle CBA
∠APC = 62º = ∠APB
∠BAP = 90° (diameter perpendicular to tangent)
In Δ APB,
∠APB + ∠BAP + ∠PBA = 180° 
⇒ ∠PBA = 180° - (90° + 62°)
⇒ ∠PBA = 28° 
∴ The measure of minor arc AC is 28° 
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Community Answer
AB is a diameter of a circle with center O. A tangent is drawn at poin...
We let θ be the angle between the tangent line and the line segment OC, then the angle between the tangent line and the line segment AB is also θ, since AB is a diameter and OC is a radius.

Since AB is a diameter, the angle at point C is a right angle. Therefore, the angle at point P is also a right angle, since the tangent line is perpendicular to the radius at the point of tangency.

Since the angle at point B is a right angle, the angle at point P is also a right angle, since BC produced meets the tangent line at point P.

Therefore, the angles at points C and P are both right angles, and the angle at point A is θ.
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