A man can thrown a stone 100 m away. the maximum height to which he can throw vertically is.?

Question

Answer

It should be 50m.use the formula R=u^2sin2(theta)/g.put theta=45 andR=100.you will get u^2=1000.then use h max=u^2/2g.you will get h=50m

Answer

Range (max) = 4 x height (max)100.                = 4 x height (max)maximum height attained = 25 m

Answer

We must have the initial velocity to solve this question

Answer

25

Answer

How

Answer

Maximum Height of a Vertical Throw

To determine the maximum height to which a man can throw a stone vertically, we need to consider the factors that affect the projectile motion of the stone.

Projectile Motion
When an object is thrown into the air, it follows a curved path due to the combined effect of its initial velocity and the force of gravity. This type of motion is known as projectile motion. The path followed by the object is called a parabola.

Factors Affecting Projectile Motion
Several factors affect the projectile motion of the stone, including:
1. Initial Velocity: The speed and direction with which the stone is thrown.
2. Angle of Projection: The angle at which the stone is thrown with respect to the horizontal.
3. Gravity: The force that pulls the stone downwards.

Vertical Component of Motion
When we consider the vertical component of the stone's motion, we only focus on the vertical displacement and the time taken. The horizontal component does not affect the maximum height of the throw.

Maximum Height Formula
The maximum height reached by an object in projectile motion can be determined using the formula:
H = (v^2 * sin^2θ) / (2 * g)

Where:
H = Maximum height
v = Initial velocity
θ = Angle of projection
g = Acceleration due to gravity (approximated as 9.8 m/s^2)

Calculating Maximum Height
To calculate the maximum height, we need to know the initial velocity and angle of projection of the man's throw. Let's assume the initial velocity is v and the angle of projection is θ.

1. Calculate the vertical component of the initial velocity:
Vy = v * sin(θ)

2. Calculate the time taken to reach the maximum height:
t = Vy / g

3. Substitute the values into the maximum height formula:
H = (Vy^2) / (2 * g)
= (v^2 * sin^2(θ)) / (2 * g)

Conclusion
The maximum height to which the man can throw vertically depends on the initial velocity and angle of projection. By calculating the vertical component of the initial velocity and using the maximum height formula, we can determine the maximum height achieved in the throw.

Answer

Is it 25m ?? @ prashu

Answer

50 m

Answer

100 m

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