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If  and h = 0.2, then solving by fourth order Runge-Kutta method:
  • a)
    The increment in y is 0.1959
  • b)
    The decrement in y is 0.1959
  • c)
    The value of y(0.2) is 1.1959
  • d)
    The value of y(0.1) is 0.8041
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Ifand h = 0.2, then solving by fourth order Runge-Kutta method:a)The i...
Range-Kutta method (R-K method):
To solve  with condition y(x0) = y0
Let 'h' denotes the interval between equidistant values of x, if the initial values are (x0 , y0), then the first increment in y is computed from the formula given by:
y1 = y0 + Δy
where Δy is the change in y given by

y0 is the intial value of y
y1 is the changed value of y
Calculation:
Given:



y1 = y0 + Δy
y1 = 1 + 0.1959 = 1.1959
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Ifand h = 0.2, then solving by fourth order Runge-Kutta method:a)The increment in y is 0.1959b)The decrement in y is 0.1959c)The value of y(0.2) is 1.1959d)The value of y(0.1) is 0.8041Correct answer is option 'C'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Ifand h = 0.2, then solving by fourth order Runge-Kutta method:a)The increment in y is 0.1959b)The decrement in y is 0.1959c)The value of y(0.2) is 1.1959d)The value of y(0.1) is 0.8041Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ifand h = 0.2, then solving by fourth order Runge-Kutta method:a)The increment in y is 0.1959b)The decrement in y is 0.1959c)The value of y(0.2) is 1.1959d)The value of y(0.1) is 0.8041Correct answer is option 'C'. Can you explain this answer?.
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