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F G and F e represent gravitational and electrostatic force respectively between electron situated at a distance of 10cm. The ratio of F G /F e is of the order.?
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F G and F e represent gravitational and electrostatic force respective...
Calculation of ratio of FG/Fe between electrons at a distance of 10cm

To calculate the ratio of gravitational force (FG) and electrostatic force (Fe) between two electrons situated at a distance of 10cm, we can use the following formulae:

FG = G * (m1 * m2) / r2

Fe = k * (q1 * q2) / r2

Where G is the gravitational constant (6.67 x 10-11 Nm2/kg2), k is the Coulomb constant (9 x 109 Nm2/C2), m1 and m2 are the masses of the electrons (9.11 x 10-31 kg each), q1 and q2 are the charges of the electrons (-1.6 x 10-19 C each), and r is the distance between the electrons (0.1m).

Calculation of FG

FG = G * (m1 * m2) / r2

FG = 6.67 x 10-11 * (9.11 x 10-31)2 / (0.1)2

FG = 2.41 x 10-48 N

Calculation of Fe

Fe = k * (q1 * q2) / r2

Fe = 9 x 109 * (-1.6 x 10-19)2 / (0.1)2

Fe = 2.3 x 10-28 N

Calculation of FG/Fe

FG/Fe = (2.41 x 10-48) / (2.3 x 10-28)

FG/Fe = 1.05 x 10-20

Therefore, the ratio of gravitational force to electrostatic force between two electrons situated at a distance of 10cm is
Community Answer
F G and F e represent gravitational and electrostatic force respective...
Fe=Kq1q2/r²
Fg=Gm1m2/r²
the ratio of them
on calculating, answer will be
4.17×10^42
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F G and F e represent gravitational and electrostatic force respectively between electron situated at a distance of 10cm. The ratio of F G /F e is of the order.?
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