Question Analysis:
To solve this problem, we need to calculate the time difference between Ram's usual driving speed and the speed at which he drives when he is 10 minutes late. The given information is that when Ram drives at a speed that is 20% less than his usual speed, he reaches his office 10 minutes late. We are asked to find out how early he would reach his office if he drives at 8/5 of his usual speed.

Given:
- Ram reaches his office 10 minutes late when he drives at a speed that is 20% less than his usual speed.
- We need to find out how early he would reach his office if he drives at 8/5 of his usual speed.

Solution:
Let's assume Ram's usual driving speed is X km/h.

Step 1: Calculate Ram's Late Arrival Time:
When Ram drives at a speed that is 20% less than his usual speed, his speed becomes (100% - 20%) = 80% of his usual speed.
So, his speed when he is 10 minutes late is 0.8X km/h.

Now, we can use the formula: Time = Distance/Speed

Let's assume the distance between Ram's home and office is D km.
When Ram drives at a speed of 0.8X km/h, the time taken to cover the distance D is given by:
Time = D/0.8X

According to the given information, Ram reaches his office 10 minutes late. So, the actual time it should have taken is:
Time + Late Arrival Time = D/0.8X + 10 minutes

Step 2: Calculate Ram's Early Arrival Time:
Now, we need to find out how early Ram would reach his office if he drives at 8/5 of his usual speed, which is (8/5)X km/h.

Using the formula: Time = Distance/Speed, the time taken to cover the distance D at a speed of (8/5)X km/h is given by:
Time = D/(8/5)X

So, the time Ram would take to reach his office if he drives at (8/5)X km/h is:
Time = D/(8/5)X

Step 3: Calculate the Time Difference:
To find out how early Ram would reach his office, we need to calculate the difference between the actual time it should have taken (when he is 10 minutes late) and the time it would take if he drives at (8/5)X km/h.

Time Difference = (D/0.8X + 10 minutes) - (D/(8/5)X)

Simplifying the above equation:
Time Difference = (5D/4X + 10 minutes) - (5D/8X)
Time Difference = (5D/4X - 5D/8X) + 10 minutes
Time Difference = (10D/8X - 5D/8X) + 10 minutes
Time Difference = (5D/8X) + 10 minutes

Step 4: Simplify the Time Difference:
To simplify further, we can take out the common factor of D/8X from the term (5