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In the figure above, the circle with center O has a circumference of 50, and AB = BC. What is the length of arc AB?
    Correct answer is '18.8'. Can you explain this answer?
    Verified Answer
    In the figure above, the circle with center O has a circumference of 5...

    Let's start by drawing the three radii OA, OB, and OC. Since these radii are all congruent, and because AB = BC, the triangles AOB and COB are congruent (by the SSS Theorem). This implies that OB bisects angle ABC, so the base angles of both isosceles triangles must have measure 45°/2 = 22.5°. Therefore, angle AOB, which is the central angle for arc AB, must have measure 180° - 22.5° - 22.5° = 135°. Now we can use the fact that the circumference of the circle is 50 to find the length or arc AB.

    Let and cross multiply: 360x = 6,750
    Divide by 360: x = 75/4 = 18.75 or 18.8
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    In the figure above, the circle with center O has a circumference of 5...

    Let's start by drawing the three radii OA, OB, and OC. Since these radii are all congruent, and because AB = BC, the triangles AOB and COB are congruent (by the SSS Theorem). This implies that OB bisects angle ABC, so the base angles of both isosceles triangles must have measure 45°/2 = 22.5°. Therefore, angle AOB, which is the central angle for arc AB, must have measure 180° - 22.5° - 22.5° = 135°. Now we can use the fact that the circumference of the circle is 50 to find the length or arc AB.

    Let and cross multiply: 360x = 6,750
    Divide by 360: x = 75/4 = 18.75 or 18.8
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    In the figure above, the circle with center O has a circumference of 50, and AB = BC. What is the length of arc AB?Correct answer is '18.8'. Can you explain this answer?
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