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If P √3Q √5 R √15 S=1/(1 √3 √5) then the value of P is (a) 7/11 (b) 3/11 (c) -1/11 (d) -2/11?
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If P √3Q √5 R √15 S=1/(1 √3 √5) then the value of P is (a) 7/11...
Given:
P √3Q √5 R √15 S = 1/(1 √3 √5)

To find:
The value of P

Explanation:
To find the value of P, we need to simplify the given expression and isolate P on one side of the equation.

Simplification:
The expression on the left side of the equation can be simplified using the properties of square roots.

√3Q √5 R √15 = √(3Q * 5 * 15) (Product rule of square roots)
= √(225Q) (Simplifying the product)
= 15√Q (Simplifying the square root)

Now, the equation becomes:

P * 15√Q * S = 1/(1 √3 √5)

Isolating P:
To isolate P, we need to move all the other terms to the right side of the equation.

P = 1/(1 √3 √5)/(15√Q * S)
= 1/(1 √3 √5) * 1/(15√Q * S)
= 1/(1 * √3 * √5 * 15√Q * S)
= 1/(15√(3 * 5) * √Q * S)
= 1/(15√15 * √Q * S)
= 1/(15√(15Q) * S)
= 1/(15S√(15Q))

Therefore, the value of P is 1/(15S√(15Q)).

Answer:
The value of P is 1/(15S√(15Q)).
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If P √3Q √5 R √15 S=1/(1 √3 √5) then the value of P is (a) 7/11 (b) 3/11 (c) -1/11 (d) -2/11?
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If P √3Q √5 R √15 S=1/(1 √3 √5) then the value of P is (a) 7/11 (b) 3/11 (c) -1/11 (d) -2/11? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about If P √3Q √5 R √15 S=1/(1 √3 √5) then the value of P is (a) 7/11 (b) 3/11 (c) -1/11 (d) -2/11? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If P √3Q √5 R √15 S=1/(1 √3 √5) then the value of P is (a) 7/11 (b) 3/11 (c) -1/11 (d) -2/11?.
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