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What is the approximate distance between the points (4, -3) and (-6, 5) in the standard (x, y) coordinate plane?
- a)8.92
- b)12.81
- c)16.97
- d)17.95
- e)19.22
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
What is the approximate distance between the points (4, -3) and (-6, 5...
Distance between Two Points
To find the distance between two points in the standard (x, y) coordinate plane, we can use the distance formula. The distance formula is derived from the Pythagorean theorem and calculates the straight-line distance between two points.
Given Points
Point 1: (4, -3)
Point 2: (-6, 5)
Distance Formula
The distance formula is given as:
Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Calculations
Substitute the given points into the formula:
Distance = sqrt((-6 - 4)^2 + (5 - (-3))^2)
Distance = sqrt((-10)^2 + (8)^2)
Distance = sqrt(100 + 64)
Distance = sqrt(164)
Distance ≈ 12.81
Therefore, the approximate distance between the points (4, -3) and (-6, 5) in the standard (x, y) coordinate plane is approximately 12.81 units. This corresponds to option 'B'.
To find the distance between two points in the standard (x, y) coordinate plane, we can use the distance formula. The distance formula is derived from the Pythagorean theorem and calculates the straight-line distance between two points.
Given Points
Point 1: (4, -3)
Point 2: (-6, 5)
Distance Formula
The distance formula is given as:
Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Calculations
Substitute the given points into the formula:
Distance = sqrt((-6 - 4)^2 + (5 - (-3))^2)
Distance = sqrt((-10)^2 + (8)^2)
Distance = sqrt(100 + 64)
Distance = sqrt(164)
Distance ≈ 12.81
Therefore, the approximate distance between the points (4, -3) and (-6, 5) in the standard (x, y) coordinate plane is approximately 12.81 units. This corresponds to option 'B'.
Community Answer
What is the approximate distance between the points (4, -3) and (-6, 5...
To solve this problem, use the distance formula which states that for any two points (x1, y1) and (x2, y2), the distance between them, d, is given by 
Therefore the distance between (4, -3) and (-6, 5) is 
which equals √164, or about 12.81. Another way to look at this problem would be to draw a picture and use the Pythagorean Theorem to find the hypotenuse of the triangle that is formed from the given points.
Therefore the distance between (4, -3) and (-6, 5) is which equals √164, or about 12.81. Another way to look at this problem would be to draw a picture and use the Pythagorean Theorem to find the hypotenuse of the triangle that is formed from the given points.
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What is the approximate distance between the points (4, -3) and (-6, 5) in the standard (x, y) coordinate plane?a)8.92b)12.81c)16.97d)17.95e)19.22Correct answer is option 'B'. Can you explain this answer?
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